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dangina [55]
2 years ago
14

As a result of the gold foil experiment, it was concluded that an atom(1) contains protons, neutrons, and electrons(2) contains

a small, dense nucleus(3) has positrons and orbitals(4) is a hard, indivisible sphere
Chemistry
1 answer:
grin007 [14]2 years ago
8 0
The answer is (2). If you recall Rutherford's gold foil experiment, remember that a stream of positively charged alpha particles were shot at a gold foil in the center of a detector ring. The important observation was that although most of the particles passed straight through the foil without being deflected, a tiny fraction of the alpha particles were deflected off the axis of the shot, and some were even deflected almost back to the point from which they were shot. The fact that some of the alpha particles were deflected indicated a positive charge (because same charges repel), and the fact that only a small fraction of the particles were deflected indicated that the positive charge was concentrated in a small area, probably residing at the center of the atom.
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Please help fast! I will give brainliest!
Artemon [7]

Explanation:

- 186 kj your answer

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3 0
3 years ago
What is the rate law for the reaction below:A + B + C Dif the following data were collected?Exp [A]0 [B]0 [C]0 Initial Rate1 0.4
otez555 [7]

Answer:

rate = k  [A] [B] ³

Explanation:

Set up a table with the data given in the question to study the dependence of the reaction rate on the concentrations of reactants.

[A]             [B]             [C]             Rate           Experiment #

0.4            1.2             0.7          2.32 x 10⁻³        (1)

1.3            1.2             0.9          7.54 x 10⁻³        (2)

0.4             4.1            0.8          9.25 x 10⁻²        (3)

1.3              1.2             0.2         7.54 x 10⁻³        (4)

The rate law will have the form : rate =  k [A] ^x   [B]  ^y    [C]   ^z

Comparing experiments (2) and (4) we have to conclude that  the rate  is zero order with respect to  [C]  since keeping [A]  and [B]  the same and varying [C] did not change the rate (i.e ,no dependence on  [C]) .

Now we know the rate law has the form rate =  k [A] ^x  [B]  ^y

Comparing (1) and (4) we keep [B] constant and increase [A] by a factor of  1.3/.4 = 3.25 and the rate increased by a factor of 0.00754 / 0.00232 =3.25, so we can conclude that the rate law is first order with respect to  [A]

Finally, comparing (1) and (3) while keeping  [A]  constant  increasing [B] by a factor of 4.1/1.2 = 3.416, the rate increased by a factor of 0.0925/0.00232 = 40, it is not entirely clear the dependence with respect to  [B] .

In this case we can always set up the following equation which is obtained by dividing  equation (3) by (1)

(4.1 / 1.2)^x = 0.0925/0.00232

taking natural log to both sides of the equation

x ln 3.4167 = ln 40

x = 3.69/1.23 = 3

So the dependence with respect to   [C] is three.

The rate law is :

rate = k  [A] [B] ³

6 0
3 years ago
aqueous lithium hydroxide solution is used to purify air (remove co2) in spacecrafts and submarines. the pressure of carbon diox
oksano4ka [1.4K]

The mass of the water is 1580 g.

<h3>What is the amount of water formed?</h3>

We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from  7.9 x 10-3 atm to  1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.

Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm

Using;

PV = nRT

n = PV/RT

n = 7.78 * 10^-3 atm *  2.4 x10^5 l/0.082 * (39 + 273)

n = 85 moles

Since 1 mole of carbon dioxide produces 1 mole of water

85 moles of carbon dioxide produces 85 mole of water

Mass of water produced = 85 mole  * 18 g/mol

= 1580 g

Learn more about ideal gas equation:brainly.com/question/4147359

#SPJ1

6 0
1 year ago
Hydrogen is special because it can act like two groups, _____<br> and _____
Vedmedyk [2.9K]

Answer: gas and alkaline earth metal

Explanation:

4 0
2 years ago
Enter the atomic symbol, including mass number and atomic number, for iodine-125.
ICE Princess25 [194]

Answer:

Explanation:

Iodine - 125

The atomic symbol of iodine is ¹²⁵₅₃ I

The symbol for iodine is I

The atomic number of iodine is 53,

and the atomic mass of iodine is 125 .

<u>The representation of the atomic symbol is as, the atomic mass is written in uppercase and the atomic number is written in lower case , followed by the symbol of the element .</u>

Iodine is a radio active element , used for many biological process .

It is the second largest -lived radioisotope of iodine .

The first is iodine-129 .

3 0
3 years ago
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