Moving with a speed of v km/hour, a train travels the distance between the points A and B, which is 600 km, in t hours. Find the
1 answer:
<h2>Formula which describes v in terms of t is 
</h2>
Explanation:
A train travels the distance between the points A and B, which is 600 km
Distance between A and B = 600 km
Speed of train = v
Time taken by train = t
We know that
Distance traveled = Speed of travel x Time taken
600 = v x t
Formula which describes v in terms of t is
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Explanation:
1/R = 1/R1 + 1/ R2
1/R = 1/960 + 1/640
1/R = 5 / 1920
<h3> R = 384 ohm </h3>So , Req = 384 + R3
Req = 384 + 180
<h3> Req = 564 ohm</h3>Answer:
b) a = 52.26 m / s², a ’= 13.06 m / s², c) N = 2.79 10⁴ N, d) N = 1.89 10³ N
Explanation:
a) In the attached we can see the free body diagrams for the two positions, position A in the lower part of the circle and position B in the upper part of the circle
b) Let's start at point A
Let's use that the acceleration is centripetal
a = v² / r
let's calculate
a = 28² / 15.0
a = 52.26 m / s²
as they relate it is centripetal it is directed towards the center of the circle, therefore for this point it is directed vertically upwards
Point B
a ’= 142/15
a ’= 13.06 m / s²
in this case the acceleration is vertical downwards
c) The values of the normal force
point A
let's use Newton's second law
∑ F = m a
N- W = m a
N = mg + ma
N = m (g + a)
N = 450.0 (9.8 + 52.25)
N = 2.79 10⁴ N
d) Point B
-N -W = m (-a)
N = ma -m g
N = m (a-g)
N = 450.0 (14.0 - 9.8)
N = 1.89 10³ N
