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horsena [70]
2 years ago
5

If your heart is beating at 76. 0 beats per minute, what is the frequency of your heart's oscillations in hertz?

Physics
1 answer:
nikitadnepr [17]2 years ago
5 0

If the heart is beating at 76. 0 beats per minute, the Frequency of heart's oscillations in hertz is 1.25 Hertz.

The Frequency is defined as the number of oscillations completed in 1s.

Our heart beats continuously giving rise to the frequency of the heart.

Measuring frequency would be possible if we measure the time in seconds.

75 beats per minute means that 75 beats occur in 60s.

Frequency = Number of beats / Total time taken

Frequency = 75 / 60

Frequency = 1.25 Hz

Hence, number of beats per second is 1.25 Beats.

Beats per second or Cycles per second is same as the frequency of oscillation called as Hertz (Hz)

Hence, frequency of the heart oscillation is 1.25 Hertz (Hz).

Learn more about Frequency here, brainly.com/question/14316711

#SPJ4

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Answer:

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Explanation:

Affirmations

a) true. The orbits are accurate in the Bohr model and probabilistic in quantum mechanics

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3 years ago
Four copper wires of equal length are connected in series. Their cross-sectional areas are 0.7 cm2 , 2.5 cm2 , 2.2 cm2 , and 3 c
Travka [436]

Answer:

22.1 V

Explanation:

We are given that

A_1=0.7 cm^2=0.7\times 10^{-4} m^2

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A_3=2.2 cm^2=2.2\times 10^{-4} m^2

A_4=3 cm^2=3\times 10^{-4} m^2

Using 1cm^2=10^{-4} m^2

We know that

R=\frac{\rho l}{A}

In series

R=R_1+R_2+R_3+R_4

R=\frac{\rho l}{A_1}+\frac{\rho l}{A_2}+\frac{\rho l}{A_3}+\frac{\rho l}{A_4}

R=\frac{\rho l}{\frac{1}{A_1}+\frac{1}{A_2}+\frac{1}{A_3}+\frac{1}{A_4}}

Substitute the values

R=\rho A(\frac{1}{0.7\times 10^{-4}}+\frac{1}{2.5\times 10^{-4}}+\frac{1}{2.2\times 10^{-4}}+\frac{1}{3\times 10^{-4}})

R=\rho l(2.62\times 10^4)

V=145 V

I=\frac{V}{R}=\frac{145}{\rho l(2.62\times 10^4)}

Voltage across the 2.5 square cm wire=IR=I\times \frac{\rho l}{A_2}

Voltage across the 2.5 square cm wire=\frac{145}{\rho l(2.62\times 10^4)}\times \frac{\rho l}{2.5\times 10^{-4}}=22.1 V

Voltage across the 2.5 square cm wire=22.1 V

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3 years ago
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Answer:

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