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OverLord2011 [107]
3 years ago
6

How many photons per second are emitted by the antenna of a microwave oven if its power output is 1.00 kw at a frequency of 2515

mhz?
Physics
1 answer:
Norma-Jean [14]3 years ago
8 0
The power of the antenna is
P=1.00 kW=1000 W
and since the power is the emitted energy divided by the time, the energy emitted per second is
E=Pt = (1000 W)(1 s)=1000 J

The frequency of the emitted photons is
f=2515 MHz=2.515 \cdot 10^9 Hz
So the energy of a single photon is
E_1=hf=(6.6 \cdot 10^{-34} Js)(2.515 \cdot 10^9 Hz)=1.66 \cdot 10^{-24} J

Therefore, to find the number of emitted photons per second, we should divide the total energy emitted by the antenna in 1 second by the energy of a single photon:
N= \frac{E}{E_1}= \frac{1000 J}{1.66 \cdot 10^{-24} J}=  6.02 \cdot 10^{26}
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