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ikadub [295]
3 years ago
5

Which of the following is a type of renewable energy?

Physics
2 answers:
amid [387]3 years ago
4 0
Answer is c hydroelectric
harina [27]3 years ago
3 0
The answer is C Hydroelectric
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Metals in group 2 on the period table most commonly form which type
LuckyWell [14K]

Answer:

alkaline earth metals

Group 2 metals, the alkaline earth metals, have 2 valence electrons, and thus form M2+ ions. The halogens, Group 17 , reach a full valence shell upon reduction, and thus form X− ions

Explanation:

6 0
3 years ago
When ___ attacks the surface of a metal, it becomes tarnished.​
alexandr1967 [171]

Answer:corrosion (i believe)

Explanation:

6 0
3 years ago
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You are attempting to row across a stream in your rowboat. Your paddling speed relative to still water is 3.0 m/s (i.e., if you
Nataliya [291]

Answer:

Please check the attached file for the diagram

Explanation:

The velocity of the of the rowboat V_{tot}  through the river is the resultant velocity. It is obtained taking a vector sum of the velocity in still water and the velocity of the river.

There are several ways to take this vector sum, but the question makes it simple for us to use Pythagoras's theorem because the East and North directions are perpendicular to each other.

Hence;

V_{tot}^2=V_{still}^2+V_{w}^2\\V_{tot}^2=3^2+4^2

V_{tot}=\sqrt{3^2+4^2}\\ V_{tot}=\sqrt{25}=5m/s

6 0
3 years ago
The balmer series is formed by electron transitions in hydrogen that
RSB [31]

Answer:

The Balmer series refers to the spectral lines of hydrogen, associated to the emission of photons when an electron in the hydrogen atom jumps from a level n \geq 3 to the level n=2.

The wavelength associated to each spectral line of the Balmer series is given by:

\frac{1}{\lambda}=R_H (\frac{1}{2^2}-\frac{1}{n^2})

where R_H is the Rydberg constant for hydrogen, and where n is the initial level of the electron that jumps to the level n = 2.

The first few spectral lines associated to this series are withing the visible part of the electromagnetic spectrum, and their wavelengths are:

656 nm (red, corresponding to the transition 3 \rightarrow 2)

486 nm (green, 4 \rightarrow 2)

434 nm (blue, 5 \rightarrow 2)

410 nm (violet, 6 \rightarrow 2)

All the following lines lie in the ultraviolet part of the spectrum. The limit of the Balmer series, corresponding to the transition \infty \rightarrow 2, is at 364.6 nm.

4 0
3 years ago
A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s
DanielleElmas [232]

a) 1.48 m/s

The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

v_{max}=\omega A

where

v_{max} is the maximum speed

\omega is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s, where f is the frequency

A=0.600 mm=6\cdot 10^{-4} m is the amplitude

Therefore, the maximum speed is

v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s

b)  3.0\cdot 10^{-5} J

The fly's maximum kinetic energy is given by

K=\frac{1}{2}mv_{max}^2

where

m=0.0270 g=2.7\cdot 10^{-5} kg is the mass of the fly

v_{max}=1.48 m/s is the maximum speed

Substituting into the equation, we find

K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J

7 0
3 years ago
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