Explanation:
(a)   Formula to calculate the density is as follows.
             
                        = 
                      = 
Now, calculate the charge as follows.
             
                       = 
                       =  C
 C
or,                   = 101.06 nC
(b)  For r = 6.50 cm, the value of charge will be calculated as follows.
                 
                           = 
                           = 7.454 
 
        
             
        
        
        
Answer:
a. P.E = 3430Joules. 
b. Workdone = 3430Nm
Explanation:
<u>Given the following data;</u>
Mass = 70kg
Distance = 5m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the potential energy;
Potential energy = mgh
P.E = 70*9.8*5
<em>P.E = 3430J</em>
b. To find the workdone;
Workdone = force * distance 
But force = mass * acceleration
Force = 70*9.8
Force = 686 Newton.
Workdone = 686 * 5
<em>Workdone = 3430Nm</em>
 
        
             
        
        
        
Answer:
The magnitude of the gravitational force is 4.53 * 10 ^-7 N
Explanation:
Given that the magnitude of the gravitational force is F = GMm/r²
mass M = 850 kg
mass m = 2.0 kg
distance d = 1.0 m , r = 0.5 m
 F = GMm/r²
Gravitational Constant G = 6.67 × 10^-11 Newtons kg-2 m2. 
F = (6.67 × 10^-11 * 850 * 2)/0.5²
F = 0.00000045356 N
F = 4.53 * 10 ^-7 N
 
        
             
        
        
        
Answer:
a=1.25m/s²
Explanation:
GIVEN DATA
vi=10m/s
vf=15m/s
S=5m
TO FIND
a=?
SOLUTION
by using third equation of motion
2as=(vf)²-(vi)²
2a(5m)=(15m/s)²-(10m/s)²
10m×a=225m²/s²-100m²/s²
10m×a=125m²/s²
a=
a=12.5m/s²
 
        
             
        
        
        
Answer:
The voltage increases by a factor of three.
Explanation: