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natka813 [3]
2 years ago
11

Determine the primary means of melting that would occur at divergent boundaries, convergent boundaries, and within a plate (intr

aplate). drag the appropriate labels to their respective targets.
Chemistry
1 answer:
Schach [20]2 years ago
8 0

By determining the primary means of melting that would occur at divergent boundaries and the appropriate labels to the respective Convergent plate boundary.

What is the Convergent plate boundary?

As the plate delves deeper into the convergent boundary, pressure and temperature rise along with it. When the pore water is released, this contributes to partial melting.

As a result, when the situation is at the melting curve, a rise in temperature will result in a large partial melt because of the presence of water. As seen in the wet peridotite melting curves in the aforementioned curves.

Only the peridotite's temperature changes during intraplate melting, not the pressure. Therefore, as the temperature rises, it will begin to melt.

Decompression causes melting at diverging boundaries. Temperature plays no part in this. As the plate delves deeper into the convergent boundary, pressure and temperature rise along with it.

When the pore water is released, this contributes to partial melting. As a result, when the situation is at the melting curve, a rise in temperature will result in a large partial melt because of the presence of water. As seen in the wet peridotite melting curves in the aforementioned curves.

Only the peridotite's temperature changes during intraplate melting, not the pressure. Therefore, as the temperature rises, it will begin to melt Decompression causes melting at diverging boundaries. Temperature plays no part in this.

Hence, the answer is Convergent plate boundary

Learn more about Convergent plate boundary,

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The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this react
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Answer:

The rate of the reaction increased by a factor of 1012.32

Explanation:

Applying Arrhenius equation

ln(k₂/k₁) = Ea/R(1/T₁ - 1/T₂)

where;

k₂/k₁ is the ratio of the rates which is the factor

Ea is the activation energy = 274 kJ/mol.

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T₂ is the final temperature = 293⁰C = 566 k

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Substituting this values into the equation above;

ln(k₂/k₁) = 274000/8.314(1/504 - 1/566)

ln(k₂/k₁) = 32956.4589 (0.00198-0.00177)

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k₂/k₁ = exp(6.92)

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The rate of the reaction increased by 1012.32

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A sample of a pure element has a mass of 45.6g and contains 4.19 x 10 23 atoms. Identify the element.
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<h2>Answer:</h2>

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<h2>Explanation:</h2>

<em>To identify the element based on the informartion given, we have to find the molar mass since this mass is unique to each element.</em>

            Molar mass = mass ÷ moles

<em>We already know the mass based on the question, as such we now need to find the # of moles.</em>

           Since 1 mole contains 6.02214 × 10²³ atoms

      then let  x moles contain 4.19 × 10²³ atoms <em>(given in the question)</em>

<em>     </em><em> </em>   ⇒   x =  (4.19 × 10²³ atoms  ×  1 mol) ÷ 6.02214 × 10²³ atoms

              x  =  0.69577 mol

<em>Now that we have the moles we can substitute it into the molar mass equation and solve for the molar mass.</em>

           ⇒ molar mass = 45.6 g ÷ 0.69577 mol

           ⇒ molar mass ≈  65.54 g/mol

                    This molar mass is closest to that of ZINC.

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