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Chemistry

1 answer:

swat323 years ago

3 0

Answer:

its only 25

Explanation:

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If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer

Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0

3 years ago

The notation for a particular nucleus is r3785b. in an electrically neutral atom. How many electrons are in orbit about this nuc

Serhud [2]

$^{85}_{37}Rb$ has 37 electrons in the orbit about its nucleus.

<h3>How to write an atomic symbol with atomic mass and atomic number?</h3>

Atomic mass is the total number of neutrons and protons present in the nucleus of an element.

The atomic number is the total number of protons present in the nucleus of an element.

For writing an atomic symbol, atomic mass is written on the top left of the atomic symbol, and the atomic number is written on the downside of the left of the symbol.

$^{Atomic mass}_{Atomic number}X$

An electrically neutral atom is an atom that has an equal number of electrons as well as protons.

Thus from the above conclusion we can say that $^{85}_{37}Rb$ has 37 electrons.

Learn more about Atomic mass and atomic number here:

brainly.com/question/3187640

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3 0

2 years ago

Give the nuclear symbol for the isotope of silicon for which a=29? Enter the nuclear symbol for the isotope (e.G., 42he).

quester [9]

The mass number is the summation of number of proton and neutron present in a nucleus of an atom. For the neutral atom the number of positive charge (number of proton) must be equal to the number of electrons. The number of electrons present in an atom is the atomic number of the atom. The standard way to express the mass number (a) and atomic number (m) of a atom (say X) is $x^{a}_{m}$ . Now for silicon number of electron or atomic number is 14. And the mass number (a) given 29. Thus the expression nucleus of silicon will be $Si^{29}_{14}$