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shusha [124]
3 years ago
15

Use the helium-4 isotope to define atomic number and mass number. Why does knowledge of the atomic number enable us to deduce th

e number of electrons present in an atom?
Chemistry
1 answer:
Zanzabum3 years ago
3 0

<u>Answer:</u> The atomic number of helium atom is 2 and mass number of helium atom is 4.

<u>Explanation:</u>

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.  It is represented by the symbol 'Z'

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.  It is represented by the symbol 'A'

Mass number = Number of protons + Number of neutrons

The general representation of an isotope is given as _Z^A\textrm{X}

where,

A = mass number of element

Z = atomic number of element

X = symbol of the element

We are given:

An isotope of helium having formula of _2^4\textrm{He}

where,

Atomic number of helium = 2 = Number of protons = Number of electrons

Mass number of helium = Number of protons + Number of neutrons

4 = 2 + Number of neutrons

Number of neutrons = 4 - 2 = 2

Hence, the atomic number of helium atom is 2 and mass number of helium atom is 4.

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A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158
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Answer:

b. The final state of the substance is a gas.

d. The sample is initially a liquid. One or more phase changes will occur.

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  • Normal boiling point: 111.65 K

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4 0
2 years ago
What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?
djverab [1.8K]

The empirical formula of the compound is CHCl₃.

<h3>Calculation:</h3>

Given,

Mass of carbon = 5.03 g

Mass of hydrogen = 0.42 g

Mass of chlorine = 44.5 g

Molecular weight of carbon = 12 g

Molecular weight of hydrogen = 1 g

Molecular weight of chlorine = 35.4 g

First, calculate the moles of each element,

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Moles of carbon = 5.03/12 = 0.42

Moles of hydrogen = 0.42/1 = 0.42

Moles of chlorine = 44.5/ 35.4 = 1.26

Divide the moles of each element by the smallest number of moles,

0.42 mol of C/ 0.42 = 1 C

0.42 mol of H/ 0.42 = 1 H

1.26 mol of Cl/0.42 = 3 Cl

The ratio of elements is 1:1:3

Therefore the empirical formula of the compound will be CHCl₃.

Learn more about empirical formula here:

brainly.com/question/20708102

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