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2 years ago

If an initial cardioversion attempt is unsuccessful in a 33-pound child, you should repeat the procedure using ___ joules.

1 answer:

algol132 years ago

8 0

If an initial cardioversion attempt is unsuccessful in a 33-pound child, you should repeat the procedure using 30 joules.

Cardioversion

Cardioversion is a medical therapy that uses medications or electricity to restore a normal heart rhythm to someone who has an abnormally high heart rate (tachycardia) or another cardiac arrhythmia. Synchronized electrical cardioversion restores the activity of the heart's electrical conduction system by applying a therapeutic dosage of electric current to the heart at a specified point in the cardiac cycle. (Defibrillation is the most efficient form of resuscitation for cardiac arrest caused by ventricular fibrillation and pulseless ventricular tachycardia. It delivers a therapeutic dosage of electric current to the heart at an unpredictable point in the cardiac cycle. Chemical cardioversion, also known as pharmacologic cardioversion, substitutes antiarrhythmic drugs for an electrical shock.

To learn more about cardioversion refer here:

brainly.com/question/11601470

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A train rolls to a stop along a horizontal track without the conductor applying the brakes. What answer choice BEST explains why

Naya [18.7K]

Answer:

Explanation:

Friction always eventually stops whatever is in motion.

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4 years ago

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9 m/s^{2$

$b=2.267 m/s$

$c=0.44 m$

Substituting the known values:

$t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.609 s$ (7)

Substituting (7) in (1):

$x=(3.10 m/s)cos(47\°)(0.609 s)$ (8)

We finally find the horizontal distance traveled by the venom:

$x=1.289 m$

7 0

4 years ago

A 0.6 kg ball is initially at rest on a frictionless, horizontal surface. It is struck by a 0.4 kg ball initially moving with a

Dafna1 [17]

Answer:

140

Explanation:

7 0

4 years ago

football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a

valkas [14]

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

Given the following data;

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

$Momentum = mass * velocity$

a. To find the momentum of A;

$Momentum \; A = 110 * 2$

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

$Momentum \; B = 120 * 0$

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

$Total \; momentum = Momentum \; A + Momentum \; B$

Substituting into the equation, we have;

$Total \; momentum = 220 + 0$

Total momentum = 220 Kgm/s. 

7 0

3 years ago

On a windy day, the wind turbine transfers 78 W of power. Calculate the amount of energy the turbine transfers in 10s.

tangare [24]

Answer:

Energy = 780 Joules

Explanation:

Given the following data;

Power = 78 Watts

Time = 10 seconds

To find the energy transferred;

Energy refers to the amount or quantity of power which is being consumed by an individual, group of people or organization over a specific period of time.

Mathematically, energy is given by the formula;

Energy = power * time

Energy = 78 * 10

Energy = 780 Joules

Therefore, the amount of energy the turbine transferred is 780 Joules

4 0

3 years ago