Visible light with a wavelength of 480 nm appears as what color?
1 answer:
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Answer:
For carbon 12
ΔV1 = 2265.31 V
ΔV2 = 362.5 V
For carbon 14
ΔV1 = 1941.7 V
ΔV2 = 310.67 V
Explanation:
The complete explanations are given in the attachment below. The formulae for the accelerating potential ΔV1 and ΔV2 are derived and the necessary parameters are substituted into the derived equations.
