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alexira [117]
1 year ago
12

An astronaut sings a song upon arriving on Planet Mongo. When her vocal cord produces an oscillation at 600 Hertz, she detects t

he wavelength of the sound wave generated to be 35 cm. The speed of sound on the planet is
Physics
1 answer:
Paraphin [41]1 year ago
3 0

The speed of sound on planet is 210 m/s.

<h3>What is Oscillation?</h3>

Oscillation is the repeating or periodic change of a quantity around a central value or between two or more states, often in time. Alternating current and a swinging pendulum are two common examples of oscillation.

There are 3 main types of Oscillation –

  • Free
  • damped
  • forced oscillation

f = frequency = 600 Hz

lambda = wavelength = 35 cm = 0.35 m

Now,

V = speed = f × lambda = 210 m/s

Hence, speed of sound on planet is 210 m/s.

to learn more about oscillation go to -

brainly.com/question/12622728

#SPJ4

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Answer:

Explanation:

<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>

<em>Displacement is the difference in the object's position from one time to another.</em>

<em>Distance is the total amount the object has traveled in a certain period of time.</em>

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5 0
2 years ago
Charge g is distributed in a spherically symmetric ball of radius a. (a) Evaluate the average volume charge density p. (b) Now a
nasty-shy [4]

Answer:

Explanation:

The volume of a sphere is:

V = 4/3 * π * a^3

The volume charge density would then be:

p = Q/V

p = 3*Q/(4 * π * a^3)

If the charge density depends on the radius:

p = f(r) = k * r

I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.

Q = \int\limits^{2*\pi}_0\int\limits^\pi_0  \int\limits^r_0 {k * r} \, dr * r*d\theta* r*d\phi

Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0  \int\limits^r_0 {r^3} \, dr * d\theta* d\phi

Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 {\frac{r^4}{4}} \, d\theta* d\phi

Q = k *\int\limits^{2*\pi}_0 {\frac{\pi r^4}{4}} \,  d\phi

Q = \frac{\pi^2 r^4}{2}}

Since p = k*r

Q = p*π^2*r^3 / 2

Then:

p(r) = 2*Q / (π^2*r^3)

3 0
3 years ago
You have decided to study the effect of loud noise on plant growth. You put one plant in a quiet room and the other plant in you
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3 years ago
What is the instantaneous speed of the object after the five seconds?
OverLord2011 [107]

Answer:

12.5 m/s

Explanation:

In a acceleration time graph the area under the curve gives the change in velocity of the object. Here object starts at rest and therefore initial velocity is 0. After 5 seconds acceleration is 5m/s2.

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