Answer:
72km
Explanation:
30 mins --> 30 x 60 s = 1800 s
Distance --> Speed x Time
= 40m/s x 1800s
= 72 000 m
= 72 km (1km is 1000m)
Answer:
3984875 N/C
Explanation:
Applying,
E = kq/r².................. Equation 1
Where E = Electric field, q = charge, r = distance, k = coulomb's constant.
From the question,
Given: q = 7.10 mC = 0.0071 C, r = 4.0 m
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
E = 0.0071(8.98×10⁹)/4²
E = 3984875 N/C
Hence the electric field is 3984875 N/C
Answer:
Hi Carter,
The complete answer along with the explanation is shown below.
I hope it will clear your query
Pls rate me brainliest bro
Explanation:
The magnitude of the magnetic field on the axis of a circular loop, a distance z from the loop center, is given by Eq.:
B
= NμοiR² / 2(R²+Z²)³÷²
where
R is the radius of the loop
N is the number of turns
i is the current.
Both of the loops in the problem have the same radius, the same number of turns, and carry the same current. The currents are in the same sense, and the fields they produce are in the same direction in the region between them. We place the origin at the center of the left-hand loop and let x be the coordinate of a point on the axis between the loops. To calculate the field of the left-hand loop, we set z = x in the equation above. The chosen point on the axis is a distance s – x from the center of the right-hand loop. To calculate the field it produces, we put z = s – x in the equation above. The total field at the point is therefore
B
= NμοiR²/2 [1/ 2(R²+x²)³÷² + 1/ 2(R²+x²-2sx+s²)³÷²]
Its derivative with respect to x is
dB
/dx= - NμοiR²/2 [3x/ (R²+x²)⁵÷² + 3(x-s)/(R²+x²-2sx+s²)⁵÷²
]
When this is evaluated for x = s/2 (the midpoint between the loops) the result is
dB
/dx= - NμοiR²/2 [3(s/2)/ (R²+s²/4)⁵÷² - 3(s/2)/(R²+s²/4)⁵÷²
] =0
independent of the value of s.
Distance= speed * time
So multiply speed and time to get the value of distance
20*9.8 =196 meters
