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Bumek [7]
3 years ago
11

I'll mark brainiest if you help me

Physics
1 answer:
Butoxors [25]3 years ago
5 0
Question 4 is true, question 5 is B.
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According to diagonal rule, the orbital with lowest energy in the given following is ________.
Kaylis [27]
The orbital with the lowest energy is 3s.
5 0
3 years ago
A nonconducting sphere of diameter 10.0 cm carries charge distributed uniformly inside with charge density of +5.50 µC/m3 . A pr
VLD [36.1K]

Answer:

t = 2.58*10^-6 s

Explanation:

For a nonconducting sphere you have that the value of the electric field, depends of the region:

rR:\\\\E=k\frac{Q}{r^2}

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

R: radius of the sphere = 10.0/2 = 5.0cm=0.005m

In this case you can assume that the proton is in the region for r > R. Furthermore you use the secon Newton law in order to find the acceleration of the proton produced by the force:

F=m_pa\\\\qE=m_pa\\\\k\frac{qQ}{r^2}=m_pa\\\\a=k\frac{qQ}{m_pr^2}

Due to the proton is just outside the surface you can use r=R and calculate the acceleration. Also, you take into account the charge density of the sphere in order to compute the total charge:

Q=\rho V=(5.5*10^{-6}C/m^3)(\frac{4}{3}\pi(0.05m)^3)=2.87*10^{-9}C\\\\a=(8.98*10^9Nm^2/C^2)\frac{(1.6*10^{-19}C)(2.87*10^{-9}C)}{(1.67*10^{-27}kg)(0.05m)^2}=9.87*10^{11}\frac{m}{s^2}

with this values of a you can use the following formula:

a=\frac{v-v_o}{t}\\\\t=\frac{v-v_o}{a}=\frac{2550*10^3m/s-0m/s}{9.87*10^{11}m/s^2}=2.58*10^{-6}s

hence, the time that the proton takes to reach a speed of 2550km is 2.58*10^-6 s

3 0
3 years ago
Are you for or against using nuclear energy?
Alecsey [184]

Answer:

Against but it really depends on the situation

4 0
3 years ago
Read 2 more answers
Answer either one or both questions! Must explain and show work to receive brainliest!
MariettaO [177]
<span>F x L = W x X whereW=weight is total load = 80, L is length from fulcrum which is the unknown and what we are solving for. x= length we know. and F equals 50 force we know. So (W*X)/F=LL equals 64</span>
3 0
3 years ago
A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1
AlekseyPX

Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

a=a_1+\dfrac{F}{m}

Where

a_1=3\ m/s^2

F=12\ kg-m/s^2

m = 7 kg

So, the correct step for obtaining a common denominator for the two fractions in the expression in solving for a is (a) and the value of a is :

a=3+\dfrac{12}{7}

a=4.71\ m/s^2

Hence, the correct option is (a).

8 0
3 years ago
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