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Rainbow [258]
2 years ago
10

A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydro

gen gas. A sample of hydrogen gas is collected over water in a eudiometer at 32. 0°c. The volume of collected gas is 43. 9 ml and the atmospheric pressure is 832 mmhg. Using the experimentally collected data, calculate r and the percent error.
Chemistry
1 answer:
lutik1710 [3]2 years ago
3 0
  • The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
  • That is approximately 0.001758.
  • Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
  • The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.
<h3>Is it true that calculations made utilizing experimental and gathered data result in a percent error? </h3>
  • Consequently, we are aware that magnesium and chloride react.
  • We create 1 as the reaction ratio is 1:2.
  • The hydrogen and 1 are more.
  • Magnesium chloride is more.
  • Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
  • Among hydrogen, there is.
  • \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
  • The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
  • Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
  • So, in this instance, we are aware that p v = n r t.
  • The r in this case equals p v over n t, thus we want to determine the r.
  • So p is 110922.24. The temperature is 305.15 and the V is 0.04  over the n is 0.001758.
  • Let's proceed with the calculations right now.
  • In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

To learn more about Magnesium chloride reactions visit:

brainly.com/question/27891157

#SPJ4

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Answer:

The reaction rate is inversely proportional to the reaction time.

Explanation:

  • The reaction rate is the change of the concentration of reactants and products with the time.

<em>∵ Reaction rate = - Δ[reactants]/Δt = Δ[products]/Δt.</em>

<em>∴ The reaction rate is inversely proportional to the time, as the reaction rate increases it will take a lower time.</em>

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3 years ago
A student mixes a 10.0 mL sample of 1.0 M NaOH with a 10.0 mL sample of 1.0 M HCl in a polystyrene container. The temperature of
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Answer:

The experimental value of ΔH is -50 kJ/mol

Explanation:

<u>Step 1: </u>Data given

Volume of 1.0 M NaOH = 10.0 mL = 0.01 L

Volume of 1.0 M HCl = 10.0 mL = 0.01 L

Temperature before mixing = 20 °C

Final temperature = 26 °C

Specific heat of solution = 4.2 J/g°C

Density = 1g/mL

<u>Step 2: </u>Calculate q

q = m*c*ΔT

⇒ with m = the mass

  ⇒ 20.0 mL * 1g/mL = 20 grams

⇒  c = specific heat of solution = 4.2 J/g°C

⇒ ΔT = T2 -T1 = 26 -20 = 6 °C

q = 20g * 4.2 J/g°C * 6°C

q = 504 J

ΔHrxn = -q  ( because it's an exothermic reaction)

ΔHrxn = -504 J

<u>Step 3:</u> Calculate number of moles

Moles = Molarity * volume

Moles = 1M *0.01 L = 0.01 moles

<u>Step 4:</u> Calculate the experimental value of ΔH

ΔHrxn = -504 / 0.01 mol = -50400 J/mol = -50.4 kJ/mol

The experimental value of ΔH is -50 kJ/mol

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You use electricity to power the blender itself, then after you power it the potential energy becomes kinetic energy which equals mechanical energy in the blender. So yes, a blender is an example of electrical to mechanical energy.

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Consider the following unbalanced redox reaction:
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Mn04 is being reduced
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How many grams of sodium formate, NaCHO2, would have to be dissolved in 3.0 L of 0.12 M formic acid (pKa 3.74) to make the solut
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Answer:

Mass_{sodium\ formate}= 889.57\ g

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:

pH=pK_a+log\frac{[salt]}{[acid]}

Given that:-

[Acid] = 0.12 M

Volume = 3.0 L

pKa = 3.74

pH = 5.30

So,  

5.30=3.74+log\frac{[sodium\ formate]}{0.12}

Solving, we get that:-

[Sodium formate] = 4.36 M

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

So,

Moles =Molarity \times {Volume\ of\ the\ solution}

So, Moles of sodium formate = 4.36*3.0 moles = 13.08 moles

Molar mass of sodium formate = 68.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

13.08\ mole= \frac{Mass}{68.01\ g/mol}

Mass_{sodium\ formate}= 889.57\ g

5 0
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