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Ratling [72]
2 years ago
5

When you apply a force, f, to an object you get an acceleration of 2m/s2. If you apply the same force to an object with twice th

e mass, what is the acceleration? m/s.
Physics
2 answers:
Effectus [21]2 years ago
8 0

  • The consequent acceleration, in, is caused by doubling the net force, F, acting on the same object.ms^-2 is going to 2a.
  • What is net force?
  • The vector sum of the forces exerted on a particle or body is known as the net force. As with all actual forces combined, its corresponding torque, or net force, forms the resultant force and affects the object's rotational motion. A torque-free resultant force may be defined by a system of forces.
  • Learn more about  net force with the help of given link:
  • brainly.com/question/18038995
  • #SPJ4
olga55 [171]2 years ago
4 0

The acceleration would be 1m/s²

<h3>What is  Force?</h3>

putting pressure to a door to push or pull it. Because force is a vector variable, it has both magnitude and direction. Force is defined as the "product of mass and acceleration of a body," in accordance with Newton's second law.

Acceleration - any process that alters velocity. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

if the force applied is f

the mass of the object is m

and acceleration is a = 2m/s²

so the relation will be,

f = ma

f = m×2

ATQ,

Now, when mass is 2m

a = f/m

a = 2m / 2m

a = 1 m/s²

to learn more about Acceleration go to - brainly.com/question/12550364

#SPJ4

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To distinguish between properties of the two major types of supernovae: massive star supernovae and white dwarf supernovae. all
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A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the s
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6 0
4 years ago
A single mass (m1 = 3.5 kg) hangs from a spring in a motionless elevator. The spring constant is k = 278 N/m. 1)What is the dist
artcher [175]
<h2>Answer:</h2>

0.126m

<h2>Explanation:</h2>

According to Hooke's law, the force (F) acting on a spring to cause an extension or compression (e) is given by;

F = k x e            -------------------(i)

Where;

k = the spring's constant.

From the question, the force acting on the spring is the weight(W) of the mass. i.e

F = W               -----------------------(ii)

<em>But;</em>

W = m x g;

where;

m = mass of the object

g = acceleration due to gravity [usually taken as 10m/s²]

<em>From equation (ii), it implies that;</em>

F = W = m x g

<em>Now substitute F = m x g into equation(i) as follows;</em>

F = k x e

m x g = k x e      ------------------(iii)

<em>From the question;</em>

m = m1 = 3.5kg

k = 278N/m

<em>Substitute these values into equation (iii) as follows;</em>

3.5 x 10 = 278 x e

35 = 278e

<em>Now solve for e;</em>

e = 35/278

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Therefore, the distance the spring is stretched from its unstretched length (which is the same as the extension of the spring) is 0.126m

3 0
3 years ago
A coffee filter of mass 1.5 grams dropped from a height of 3 m reaches the ground with a speed of 0.7 m/s. How much kinetic ener
Mademuasel [1]

The kinetic energy gained by the air molecules is 0.0437 J                

<h3 />

Given:

Mass of a coffee filter, m = 1.5 g

Height from which it is dropped, h = 3 m

Speed at ground, v = 0.7 m/s

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P =mgh

P = 1.5 × 10⁻³ kg × 9.8 m/s² × 3m

P = 0.0441 J

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E= \frac{1}{2} mv^{2}

E= \frac{1}{2}×1.4 × 10⁻³ × (0.7)²

E = 0.000343 J

The  kinetic energy Kair did the air molecules gain from the falling coffee filter is :

E = 0.000343 -  0.0441

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So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J

Learn more about kinetic energy here:

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8 0
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