Question

When a photon of light scatters off of a free stationary electron, the wavelength of the photon.

Answer 1

Wavelength of the incident photon = $\lambda = 0.025nm = 0.025 \times 10^{-9}m$

$\lambda ^{'}-\lambda = \frac{h}{m_{e}c} \times (1- cos\theta )$

Using the above formula we get Shifting wavelength $\lambda = 0.027 \times 10^{-9}m$

What is wavelength?

• In physics, the wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats. It is the distance between consecutive corresponding points of the same phase on the wave, such as two adjacent crests, troughs, or zero crossings, and is a characteristic of both traveling waves and standing waves, as well as other spatial wave patterns.
• The inverse of the wavelength is called the spatial frequency. Wavelength is commonly designated by the Greek letter lambda (λ).
• The term wavelength is also sometimes applied to modulated waves, and to the sinusoidal envelopes of modulated waves or waves formed by interference of several sinusoids.
• Assuming a sinusoidal wave moving at a fixed wave speed, wavelength is inversely proportional to frequency of the wave: waves with higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths.

To learn more about Wavelength with the given link

brainly.com/question/4112024

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Question:

A photon moving in the +x-direction, scatters off a free stationary electron. The wavelength of the incident photon is 0.0250 nm. After the collision, the electron moves at an angle α below the +x-axis, while the photon moves at an angle θ = 83.3° above the +x-axis. (Assume that the electron is traveling slow enough that the non-relativistic relationship between momentum and velocity can be used.)

(a) Find the shifting Wavelength of the incident photon