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mel-nik [20]
3 years ago
8

PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

Physics
2 answers:
almond37 [142]3 years ago
8 0

That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

yawa3891 [41]3 years ago
6 0
The red at the bottom is just the holder for the beaker. It’s not apart of the density.
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A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 375 N
spayn [35]

Answer:

The conservation of energy should be used to answer this question.

a)

At the position where the spring is unstretched, the elastic potential energy of the spring is zero.

K_1 + U_1 - W_f = K_2 +U_2\\K_1 - W_f = U_2

since U_1 and K_2 is equal to zero.

W_f = F_fx\\\\U_2 = \frac{1}{2}kx^2\\\\19 - (10)x = \frac{1}{2}(375)x^2\\\\375x^2 + 20x - 38 = 0

The roots of this quadratic equation can be solved by using discriminant.

\Delta = b^2 - 4ac\\x_{1,2} = \frac{-b \pm \sqrt{\Delta}}{2a}

x_1 = -0.346\\x_2 = 0.292

We should use the positive root, so

x = 0.292 m.

b)

We should use energy conservation between the point where the spring is momentarily at rest, and the point where the spring is unstretched.

K_2 + U_2 - W_f = K_3 + U_3\\U_2 - W_f = K_3

since the kinetic energy at point 2 and the potential energy at point 3 is equal to zero.

\frac{1}{2}kx^2 - F_fx = K_3\\K_3 = 15.987 - 2.92 = 13.067 J

Explanation:

In questions with springs, the important thing is to figure out the points where kinetic or potential energy terms would be zero. When the spring is unstretched, the elastic potential energy is zero. And when the spring is at rest, naturally the kinetic energy is equal to zero.

In part b) the cookie slides back to its original position, so the distance traveled, x, is equal to the distance in part a). The frictional force is constant in the system, so it is quite simple to solve part b) after solving part a).

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