In a displacement versus time graph, the slope of the line at any point on the graph indicates the <em>magnitude of velocity</em>.
(It can't indicate velocity completely, because the graph shows nothing about the direction of the motion.)
Answer:
Work done = 0.3142 Nm
Explanation:
Mass of Object is 50 g
Circular path of radius is 10 cm ⇒ 0.1 m
Work done = Force × Distance = ?
*Distance moved (circular path) ⇒ Circumference of the circular path
2πr = 2 × 3.142 × 0.1 ⇒ 0.6284 m
*Force that is enough to move a 50 g must be equal or more than its weight.
therefore convert 50 grams to newton = 0.5 N
Recall that; work done is force times distance
∴ 0.5 N × 0.6284 m
Work done = 0.3142 Nm
To solve this problem we will apply the concepts related to the wavelength of its third harmonic.
It describes that the wavelength is equivalent to
Here,
The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say
In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore
Finally the length of the pipe would be
Answer:
14 m/s
Explanation:
The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:
where
u = 0 is the initial speed
g = 9.8 m/s^2 is the acceleration
d = 10.0 m is the distance covered by the book
Substituting data, we find
Given:
Acceleration is uniform and acceleration (a) = 10 m/s^2
Now it has been mentioned for the first 2 secs the acceleration is 10m/s^2 .
Hence velocity= acceleration x time
Velocity= 10 x 2 = 20 m/s
Consider s as the distance traveled in the 3rd second.
Now we know s= ut+1/2(at^2)
Where s is the distance measured in m.
u is the initial velocity measured in m/sec
t is the time taken for the object to travel the above distance. This is equal to one second as we need to calculate the distance traveled between 3rd and 2nd second.
t = (3-2)= 1 sec
Substituting the given values in the above formula we get
s = 20 x1 + 1/2 (10 x 1 x 1)
s = 25 m
Thus the distance traveled by the object in the 3rd second is 25 m