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4 years ago

What is the concentration of a magnesium hydroxide solution with a pH of 12.05

Chemistry

1 answer:

chubhunter [2.5K]4 years ago

6 0

Answer:

5.6x10^–3 M

Explanation:

We'll begin by calculating the pOH of the solution. This can be achieved as shown below:

pH + pOH = 14

pH = 12.05

12.05 + pOH = 14

Collect like terms

pOH = 14 – 12.05

pOH = 1.95

Next, we shall determine the concentration of hydroxide ion OH- in the solution. This is illustrated below:

pOH = – Log [OH-]

pOH = 1.95

1.95 = – Log [OH-]

– 1.95 = Log [OH-]

[OH-] = anti log (– 1.95)

[OH-] = 0.0112 M

Finally, we can obtain the concentration of Mg(OH)2 as follow:

In solution, Mg(OH)2 will dissociates as shown below:

Mg(OH)2 —> Mg2+ + 2OH-

From the balanced equation above,

1 mole of Mg(OH)2 produced 2 moles of OH-.

Therefore, XM of Mg(OH)2 will produce 0.0112 M of OH- i.e

XM of Mg(OH)2 = 0.0112/2

XM of Mg(OH)2 = 5.6x10^–3 M

Therefore, the concentration of Mg(OH)2 is 5.6x10^–3 M

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kvasek [131]

Answer:

The statement is false

Explanation:

Number of moles of alkene = 2.31 × 85/1000 = 0.196 moles

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Given that the reaction is 1:1

1 mole of alkene reacts with 1 mole of bromine

0.196 moles of alkene should react with 0.196 moles of bromine

Hence, to achieve 100%yield, 0.196 moles of bromine and not 25mmols of elemental bromine

6 0

3 years ago

Help then I will give a brainliest

BARSIC [14]

Hopefully you get the correct answer I just need points

8 0

3 years ago

solution of a weak acid HA has initial concentration c and acid ionization constant Ka. To what concentration should the acid be

soldier1979 [14.2K]

Answer:

The concentration c is equal to Ka

Explanation:

The acid will ionize as observed in the following reaction:

HA = H+ + A-

H+ is the proton of the acid and A- is the conjugate base . The equation to calculate the Ka is as follows:

Ka = ([H+]*[A -])/[HA]

Initially we have to:

[H+] = 0

[A-] = 0

[HA] = c

During the change we have:

[H+] = +x

[A-] = +x

[HA] = -x

During balance we have:

[H+] = 0 + x

[A-] = 0 + x

[HA] = c - x

Substituting the Ka equation we have:

Ka = ([H+]*[A-])/[HA]

Ka = (x * x)/(c-x)

x^2 + Kax - (c * Ka) = 0

We must find c, having as [H+] = 1/2c. Replacing we have:

(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0

(c^2)/2 + Ka(c / 2 - c) = 0

(c^2)/2 + (-Ka * c/2) = 0

c^2 -(c*Ka) = 0

c-Ka = 0

Ka = c

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3 years ago

Tectonic activity (170 – 40 million years ago) that resulted in much of the rugged landscape of the western North America. Descr

solmaris [256]

Answer:

A process known as Subduction

Explanation:

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4 0

3 years ago

Convert 66.8g to mg ! Thank you

igor_vitrenko [27]

66.8g to mg is 66800 hope this helps

8 0

3 years ago