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Yuri [45]
3 years ago
9

In going from room temperature 25° to 35 the rate of a reaction doubles calculate the activation energy for the reaction

Chemistry
1 answer:
Pepsi [2]3 years ago
4 0

Answer:

52.9 KJmol-1

Explanation:

From;

log(k2/k1) = Ea/2.303 * R (1/T1 - 1/T2)

The temperatures must be converted to Kelvin;

T1 = 25° C + 273 = 298 K

T2= 35°C + 273 = 308 K

R= gas constant = 8.314 JK-1mol-1

Substituting values;

log 2 = Ea/2.303 * 8.314 (1/298 - 1/308)

Ea = 52.9 KJmol-1

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2 years ago
Name the two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate. Use the charges on th
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Answer:

General equation for a double-displacement reaction:  

AB + CD --> AC + BD

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Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄  

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• sodium chloride – NaCl silver nitrate – AgNO₃  

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The products formed are silver chloride and sodium nitrate.

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The products formed are silver hydroxide and sodium nitrate.

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Silver hydrogen phosphate forms a colorless solution.

Explanation:

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