<u>Analysing the Question:</u>
We are given a 250 mL solution of 0.5M K₂Cr₂O₇
Which means that we have:
0.5 Mole in 1L of the solution
0.125 moles in 250 mL of the solution <em>[dividing both the numbers by 4]</em>
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<u>Mass of K₂Cr₂O₇ in the given solution:</u>
Molar mass of K₂Cr₂O₇(Potassium Dichromate) = 194 g/mol
<em>we know that we have 0.125 moles in the 250 mL solution provided</em>
Mass = Number of moles * Molar mass
Mass = 0.125 * 194
Mass = 36.75 grams
North Dakota and Michigan because it has to be 32 Farenhieht or less to snow
Answer:
Pentafluorobenzene: 11,92 min
Benzene: 12,14 min
Explanation:
<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>
The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:
tr' = tr - 1,06min
For pentafluorobenzene:
tr' = 12,98min - 1,06min = <em>11,92 min</em>
For benzene:
tr' = 13,20 - 1,06min = <em>12,14 min</em>
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I hope it helps!
