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2 years ago

An element with the general electron configuration for its outermost electrons of ns2np1 would be in which element group?

1 answer:

8 0

Electron configuration is the electron distribution in the molecular and atomic orbital. An element with configuration ns²np¹ will be in the 3A group. Thus, option B is correct.

<h3>What is electronic configuration?</h3>

The electronic configuration has been the arrangement and distribution of the sub-atomic particle, an electron in the atomic shells.

The electronic configuration given is, ns²np¹. Here, there are three valence electrons in the outermost orbit. As it has been known that the number of the valence electron gives the number of the group.

Therefore, option B. 3A group or 13 group is the correct option.

Learn more about electronic configuration here:

brainly.com/question/11182760

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Your question is incomplete, but most probably your full question was, An element with the general electron configuration for its outermost electrons of ns2np1 would be in which group?

a. 2a

b. 3a

c. 4a

d. 5a

e. 8a

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What group is Pb (lead) in?

docker41 [41]

Answer:

Lead (Pb), a soft, silvery white or grayish metal in Group 14 (IVa) of the periodic table.

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3 years ago

(a) Calculate the energy released by the alpha decay of 222 86Rn.

Alinara [238K]

Answer:

a). The energy released by the alpha decay of 222 Rn is to 218 Po :

= 5.596 MeV

b).The energy of the alpha particle is 5.5 MeV

c) The recoil energy of Po = 0.096 MeV

Explanation:

The equation for the alpha decay of Rn to Polonium is:

$_{86}^{222}\textrm{Rn}\rightarrow$ $_{2}^{4}\textrm{He}+_{84}^{218}\textrm{Po}$

The energy of the decay process can be calculated using:

$\Delta E=\Delta mc^{2}$

$\Delta m$ = Change in the mass

Mass of Po = 218.008965 u

Mass of He = 4.002603 u

Mass of Rn = 222.017576 u

$\Delta m$ = mass of Po + mass of He - mass of Rn

= 4.002603 + 218.008965-222.017576

= - 0.006008

$\Delta E=m(931.5MeV)$

$\Delta E=-0.006008\times 931.5MeV$

= -5.596 MeV

The negative sign means energy is released during the process.

b) The energy of the alpha particle is :

$\frac{Po\ mass }{Rn\ mass}\times E$

$\frac{218.0089}{222.0175}\times \Delta E$

$\frac{218.0089}{222.0175}\times 5.596$

= 5.494 MeV

= 5.5 MeV

c).

Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.

The energy of the recoil polonium atom :

The formula for recoil energy is :

The total energy - the kinetic energy

= 5.596 - 5.5

= 0.096 MeV

7 0

3 years ago

Common units of electrical force are: A coulombs B Newtons C meters

dybincka [34]

b is the correct answer

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3 years ago

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What is the overall reaction order for this rate law: rate = k[A]2[B][C]?

dybincka [34]

Zero order are reactions in which concentration of reactant has NO effect on RATE OF REACTION.

2. First order are reactions in which concentration of one reactant is proportionate to the RATE OF REACTION.

Exp: That means when you increase the concentration of the one reactant, then the rate of reaction will increase by the same degree of extent.

3. Second order are reactions in which concentration of two reactant has an effect on the RATE OF REACTION.

Formula:

1. Zero order Rate = k

2. First order Rate = k(A)^m

3. Second order Rate = k(A)^m(B)^n

where () represents concentration

and equation is mA + nB -> Product.

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3 years ago

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Apart from cases of nuclear processes (including fission), elements cannot be broken down to form other substances.

Shtirlitz [24]

Explanation:

Element is ur answer

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3 years ago