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zubka84 [21]
3 years ago
13

What is the percent yield for a reaction if the theoretical yield of Fe2(SO4) is 33.14 g and the

Chemistry
1 answer:
Triss [41]3 years ago
4 0

Answer:

% yield = 55.82%

Explanation:

Theoretical yield = 33.14g

Actual yield = 18.5g

Percentage yield = (actual yield / theoretical yield) * 100

%yield = (18.5 / 33.14) * 100

% yield = 0.5582 * 100

% yield = 55.82%

The percentage yield of Fe₂So₄ is 55.82%

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Mercury (ii) oxide is made up of mercury and oxygen. The total mass of mercury (ii) oxide is 14.2 g, after decomposition 13.2 g of mercury were formed, therefore the mass of oxygen 1 g (14.2 g -13.2 g).
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fills a 500.mL flask with 3.6atm of carbon monoxide gas and 1.2atm of water vapor. When the mixture has come to equilibrium she
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Answer:

The answer to the question is

The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits

Explanation:

To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure

At the first trial the mixture contains

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which gives

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therefore the mixture contained

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when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂

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adding 1.8 atm CO gives 4.46 atm hence we have

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