Answer:
<span><span>22688</span>Ra→<span>l<span>22286</span></span>Rn+<span>l<span>42</span></span>He</span>
Explanation:
An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.
During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.
Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation:
<span><span>22688</span>Ra→<span>l<span>22286</span></span>Rn+<span>l<span>42</span></span>He</span>
Note that the sum of the subscripts (atomic numbers or charges) is the same on each side of the equation.
Also, the sum of the superscripts (masses) is the same on each side of the equation.
Now try figuring out Am-241
Answer:
6CO2 + 6H2O --> C6H12O6 + 6O2
C6H12O6 + O2 --> 6CO2 + 6H2O
Explanation:
The balanced form of both equations
Answer:
The length of an edge of this unit cell is 407.294 pm
Explanation:
Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.
To determine the edge length, a relationship between the radius of the atom and edge length is used.
X = R√8
Where;
X is the length of an edge of this unit cell
R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m
X = 144 X 10⁻¹²√8
X = 407.294 X 10⁻¹² m
X = 407.294 pm
Therefore, the length of an edge of this unit cell is 407.294 pm
