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BigorU [14]
2 years ago
15

If the relative humidity is 25 nd the saturation mixing ratio is 24g/kg, what is the mixing ratio?

Physics
1 answer:
levacccp [35]2 years ago
5 0

The mixing ratio is 6.

To find the answer, we have to know about the mixing ratio.

<h3>What is mixing ratio?</h3>
  • The mixing ratio must be calculated in a complex manner.
  • A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
  • The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
  • The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,

                         Rh=\frac{w}{w_s} *100

where; w is the mixing ratio and w(s) is the saturation mixing ratio.

  • In our question, it is given that,

                                    Rh=25\\w_s=24

  • Thus, the mixing ratio will be,

                            w=\frac{Rh*w_s}{100} =\frac{25*24}{100}=6

Thus, we can conclude that, the mixing ratio is 6.

Learn more about mixing ratio here:

brainly.com/question/8791831

#SPJ4

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klemol [59]

Answer:

true

Explanation:

that's the answear

3 0
2 years ago
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A 20-kg cart travels at 20 m/s in a circle with a radius of 20 m. What is the centripetal force?
Vlad1618 [11]

Centripetal force = (mass) x (speed)² / (radius)

                           = (20 kg) x (20 m/s)² / (20 m)

                           = (20 x 20 / 20)  (kg-meter/sec²)

                           = 20 newtons


5 0
3 years ago
Read 2 more answers
How will a current change if the resistance of a circuit remains constant while the voltage across the circuit decreases to half
beks73 [17]

Answer:

1. The current will drop to half of its original value.

Explanation:

The problem can be solved by using Ohm's law:

V=RI

where

V is the voltage across the circuit

R is the resistance of the circuit

I is the current

We can rewrite it as

I=\frac{V}{R}

In this problem, we have:

- the resistance of the circuit remains the same: R' = R

- the voltage is decreased to half of its original value: V'=\frac{V}{2}

So, the new current will be

I'=\frac{V'}{R'}=\frac{V/2}{R}=\frac{1}{2}\frac{V}{R}=\frac{I}{2}

so, the current will drop to half of its original value.

4 0
3 years ago
Please help and I don't mean to sound rude but, ONLY ANSWER IF YOUR GOING TO DO ALL 4 QUESTIONS
anzhelika [568]

Answer:

for first question is 2

for second question 1

for third question 2

for forth question 1

Explanation:

i hope i helped

6 0
3 years ago
A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
Karolina [17]

Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

Vd = 7.76*10^-5/1.3584*10^10

Vd = 5.71*10^-15

Therefore, the current density and speed drift are 4.9*10^-6

And 5.71*10^-15 respectively

3 0
3 years ago
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