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allochka39001 [22]
3 years ago
12

Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca

pacitor 1 are 16 volts and 16 volts The potentials of the two plates in capacitor 2 are 320 volts and 352 volts a What is the electric field inside capacitor 1
Physics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

    E = -4000 N / C

Explanation:

The potential and electric field are related

         V = - E s

          E = - V / s

we reduce the magnitudes to the SI system

          s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

          E = - 16 /0.004

          E = -4000 N / C

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Given a block of glass that is semi-circular, a laser pointer, protractor/ruler, and index card, design your own experiment to o
Charra [1.4K]

Answer:

we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

Explanation:

To design the experiment of measuring the critical angle, we describe the phenomenon, when the light passes from a medium with a higher refractive index to one with a lower index, it separates from the normal one and the Critical Angle is defined as the Angle for which the refraction occurs at 90º

            n₂ sin θ₂ = n₁ sin 90

           n₁ / n₂ = sin θ₂

As we can see, we have to measure the angle with which the laser touches the exit surface of the glass block.

Design of the experiment:

    We place the glass block on the ramp and at the top we hit the conveyor for half the angle, we climb the block on the ramp and see that the angle of incidence of lightning on the exit face changes, part of the beam comes out of the glass , we see it by dispersion in the particles of dirty in the air; Maybe the conveyor or the laser should be moved slightly so that the beam touches the point of origin on the conveyor.

   

   When we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

5 0
3 years ago
Read 2 more answers
A long wire carrying a 5.0 A current perpendicular to the xy-plane intersects the x-axis at x= - 2.0 cm . A second, parallel wir
mario62 [17]

Answer:

a . 0.35cm

b.  11.33cm

Explanation:

a. Given both currents are in the same direction, the null point lies in between them. Let x be distance of N from first wire, then distance from 2nd wire is 4-x

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in between the wires:

\frac{\mu_oi_1}{2\pi x}=\frac{\mu_oi_2}{2\pi(4-x)}\\\\5/x=\frac{3.5}{4-x}\\\\x=2.35cm\\\\N=2.35-2=0.35cm

Hence, for currents in same direction, the point is 0.35cm

b. Given both currents flow in opposite directions, the null point lies on the other side.

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:

Let x be distance of N from first wire, then distance from 2nd wire is 4+x:

\frac{\mu_oi_1}{2\pi(4+ x)}=\frac{\mu_oi_2}{2\pi x}\\\\5/(4+x)=\frac{3.5}{x}\\\\x=9.33cm\\\\N=9.33+2=11.33cm

Hence, if currents are in opposite directions the point on x-axis is 11.33cm

8 0
3 years ago
PLS HELP !!
Ira Lisetskai [31]
A because it’s basic kinetic example
4 0
3 years ago
Read 2 more answers
What is the least amount of time required for a given point on this wave to move from y = 0 to y = 12cm?
ale4655 [162]

Time t = ?

<span>When wave is moving from y = 0  to y =12 cm</span>

By using the formula,

y = 15cos [(π/12) t)] = 0,

cos [(π/12) t)] = 0 = cos (π/2), so, 

(π/12)t = π/2,

t = (π/2) (12/π) 

t = 12/2

<span>t = 6 sec</span>

<span>so 6 sec is the least amount of time required</span>

4 0
3 years ago
The distance, x, covered by a particle in time, t, is given as x=a +bc+ct^2 +dt^3
Sav [38]

Answer:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

Explanation:

Since the expression for the distance is:

x = a+b\,t+c\,t^2+d\,t^3

then:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

because we are supposed to be able to add all of the terms and get a distance.  So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.

6 0
3 years ago
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