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sergiy2304 [10]
2 years ago
11

The current through a 10-ohm resistor connected to a 120-V power supply is The current through a 10-ohm resistor connected to a

120-V power supply is 1 A. 120 A. 12 A. 10 A. none of these
Physics
1 answer:
Mazyrski [523]2 years ago
7 0

Answer:

12 A

Explanation:

V= I * R

V/R = I

120 V /10 Ω  = 12 AMPS

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A car traveling at 60 km/h will skid 30 m when its brakes are locked. if the same care is traveling at 180 km/h, what will be th
Flauer [41]
The first car travels at 60km/h and skid at 30m away from the starting point while another car is also traveling at 180km/h. Now, we need to solve for the skidding distance.
We assigned variables such as:
V1=60km/h
V2=180km/h
Skid1=30m
Skid2=?
We solve this by ratio and proportion method such as shown below:
V1/V2=skid1/skid2
60/180=30/skid2
skid2=(30*180)/60
skid2=90meters

Th answer is 90 meters.
3 0
3 years ago
Read 2 more answers
Debido al desorden en el laboratorio un científico tiene 2 termómetros diferentes pero no sabe en qué escalas están por lo que d
just olya [345]

Answer:

La escala del termómetro ''A'' es grados Celsius.

La escala del termómetro ''B'' es grados Fahrenheit.

Explanation:

Para hallar en qué escalas están los termómetros partimos de que la mezcla a la cuál se midió su temperatura mantuvo su temperatura constante.

Esto quiere decir que los termómetros están expresando la misma temperatura pero en una escala distinta.

Sabemos que dada una temperatura en grados Celsius ''C'' si la queremos convertir a grados Fahrenheit ''F'' debemos utilizar la siguiente ecuación :

F=(\frac{9}{5})C+32 (I)

Ahora, si reemplazamos y asumimos que la temperatura de 18° es en grados Celsius, entonces si reemplazamos C=18 en la ecuación (I) deberíamos obtener F=64.4 ⇒

F=(\frac{9}{5}).(18)+32=32.4+32=64.4

Efectivamente obtenemos el valor esperado. Finalmente, corroboramos que la temperatura del termómetro ''A'' está medida en grados Celsius y la temperatura del termómetro ''B'' en grados Fahrenheit.

6 0
3 years ago
Thomson's experiments accounted for: the mass of the electron the fundamental charge the force on a current-carrying wire the el
gogolik [260]

Thomson experiment he calculated the charge to mass ratio just be passing the fundamental charge through a tube

He calculated the charge to mass ratio just by finding the deflection of charge while it is passing through the constant electric field

so here we will use the deflection as following

let say it passes the field of length "L"

so here we have

t = \frac{L}{v}

now in the same time if it deflect by some distance

\delta y = \frac{1}{2}at^2

\delta y = \frac{1}{2}{eE}{m}t^2

now by solving this equation we can find e/m ratio

so here correct answer will be

the electron's charge-to-mass ratio

7 0
3 years ago
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During physical science class, ben and jerry connected three identical light bulbs in parrallel to a battery. What happens when
dmitriy555 [2]
The other two bulbs stay lit with the same brightness.
4 0
3 years ago
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A 15.0 Kg object is moved from a height of 7.00 m above thefloor to a height of 13.0 m above the floor. What is the change ingra
Pie

To solve this problem we will apply the concepts related to potential gravitational energy. This is defined as the product between mass, acceleration and change in height and can be expressed as,

\Delta PE = mg \Delta h

Here,

m = Mass

g = Gravitational acceleration

\Delta h = Height

Replacing with our values we have,

\Delta PE = (15kg)(9.81m/s^2)(13m-7m)

\Delta PE = 882.9J \approx 883J

Therefore the change in gravitational potential energy is 883J.

4 0
3 years ago
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