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3 years ago

Hyperthermic body temperature can range from 41.0°C to 42.3°C. What is this range in degrees Fahrenheit?

Physics

2 answers:

Gemiola [76]3 years ago

4 0

Answer:

To convert celcius to farenheit the formula to be used is (c*9/5)+32

we have to use this formula and we will get the final answer then do the same with the other no. also then subtract both the answer to get the final answer

IRISSAK [1]3 years ago

3 0

Answer:

Hyperthermic body:

A body which is unable to dissipate the energy that it posses or contains inside itself. As there are various techniques through which any normal body can remove the extra amount of heat from itself and maintain a balance body temperature,T.

As, we have the following formula to convert the temperature,T present in centigrade to the Fahrenheit, as follows;

T(Fahrenheit)=T(centigrade)×1.8+32,

Explanation:

So by putting the values provided in the problem, we can now resolve it as,

For the lower limit we can have,

T(Fahrenheit)=T(41)×1.8+32,
T(Fahrenheit)=105.8°F.

And for the higher limits we can resolve them as,

T(Fahrenheit)=T(42.3)×1.8+32,
T(Fahrenheit)=108.14°F.

As we have the hyperthermic body temperature range from the 105.8°F to 108.14°F.

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The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscop

Blababa [14]

Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

the distance between the lens in microscope L= 16 cm

The focal length of objective f₀ = 1.5 cm

Normal near point N = 25 cm

Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

=18/2.76

fₙ = 6.52 cm

The focal length of eye piece is 6.52 cm.

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3 years ago

Consider a rectangular ice floe 5.00 m high, 4.00 m long, and 3.00 m wide. a) What percentage of the ice floe is below the water

artcher [175]

Answer:

(a) 92 %

(b) 6.76 %

Explanation:

length, l = 4 m, height, h = 5 m, width, w = 3 m, density of water = 1000 kg/m^3

density of ice = 920 kg/m^3, density of mercury = 13600 kg/m^3

(a) Let v be the volume of ice below water surface.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of water x g = Total volume of ice block x density

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v x 1000 x g = V x 920 x g

v / V = 0.92

% of volume immersed in water = v/V x 100 = 0.92 x 100 = 92 %

(b) Let v be the volume of ice below the mercury.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of mercury x g = Total volume of ice block x

density of ice x g

v x 13600 x g = V x 920 x g

v / V = 0.0676

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Answer:

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Answer:

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2 years ago

Ann walked 1.5 miles south to her house in 0.5 hours. what is Ann's speed? what is Ann's velocity

ipn [44]

To calculate the speed and velocity of the Ann`s we use the formula,

$v= \frac{d}{t}$

Here, d is distance and t is time and v if we take it with direction then it is called velocity and if we take it without the direction then it is called speed.

Given $d=1.5 miles$ and $t=0.5 hours$ .

Substituting these values in above equation we get

$v=\frac{1.5mi }{0.5 h} = 3 mi/h$

As Ann walked towards south direction therefore, Ann`s velocity is 3 mi/h south and her speed is 3 mi/h .

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4 years ago