All categories

3 years ago

Hyperthermic body temperature can range from 41.0°C to 42.3°C. What is this range in degrees Fahrenheit?

Physics

2 answers:

Gemiola [76]3 years ago

4 0

Answer:

To convert celcius to farenheit the formula to be used is (c*9/5)+32

we have to use this formula and we will get the final answer then do the same with the other no. also then subtract both the answer to get the final answer

IRISSAK [1]3 years ago

3 0

Answer:

<u>Hyperthermic body:</u>

A body which is unable to dissipate the energy that it posses or contains inside itself. As there are various techniques through which any normal body can remove the extra amount of heat from itself and maintain a balance body temperature,T.

As, we have the following formula to convert the temperature,T present in centigrade to the Fahrenheit, as follows;

<u>T(Fahrenheit)=T(centigrade)×1.8+32,</u>

Explanation:

So by putting the values provided in the problem, we can now resolve it as,

For the lower limit we can have,

T(Fahrenheit)=T(41)×1.8+32,
T(Fahrenheit)=105.8°F.

And for the higher limits we can resolve them as,

T(Fahrenheit)=T(42.3)×1.8+32,
T(Fahrenheit)=108.14°F.

<u>As we have the hyperthermic body temperature range from the 105.8°F to 108.14°F.</u>

You might be interested in

A roller coaster car may be approximated by a block of mass m. Thecar, which starts from rest, is released at a height h above t

elena55 [62]

Answer:

The first part can be solved via conservation of energy.

$mgh = mg2R + K\\K = mg(h-2R)$

For the second part,

the free body diagram of the car should be as follows:

- weight in the downwards direction

- normal force of the track to the car in the downwards direction

The total force should be equal to the centripetal force by Newton's Second Law.

$F = ma = \frac{mv^2}{R}\\mg + N = \frac{mv^2}{R}$

where $N = 0$ because we are looking for the case where the car loses contact.

$mg = \frac{mv^2}{R}\\v^2 = gR\\v = \sqrt{gR}$

Now we know the minimum velocity that the car should have. Using the energy conservation found in the first part, we can calculate the minimum height.

$mgh = mg2R + \frac{1}{2}mv^2\\mgh = mg2R + \frac{1}{2}m(gR)\\gh = g2R + \frac{1}{2}gR\\h = 2R + \frac{R}{2}\\h = \frac{5R}{2}$

Explanation:

The point that might confuse you in this question is the direction of the normal force at the top of the loop.

We usually use the normal force opposite to the weight. However, normal force is the force that the road exerts on us. Imagine that the car goes through the loop very very fast. Its tires will feel a great amount of normal force, if its velocity is quite high. By the same logic, if its velocity is too low, it might not feel a normal force at all, which means losing contact with the track.

7 0

3 years ago

The drag force that resists the motion of a car traveling at 80 km h^- 1 is 300 N.

kobusy [5.1K]

The power require to keep the car traveling is 6,666 W.

The power of the engine at the given efficiency is 3,999.6 W.

<h3>What is Instantaneous power?</h3>

This the product of force and velocity of the given object.

The power require to keep the car traveling is calculated as follows;

P = Fv

$P = 300\ N \ \times \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\
P = 300 \ N \times 22.22 \ m/s\\\\
P = 6,666 \ W$

The power of the engine at the given efficiency is calculated as follows;

$E = \frac{P_{out}}{P _{in}} \times 100\%\\\\
60\% = \frac{P_{out}}{6,666} \times 100\%\\\\
0.6 = \frac{P_{out}}{6,666} \\\\
P_{out} = 3,999.6 \ W$

Learn more about efficiency here: brainly.com/question/15418098

8 0

2 years ago

What's the difference between Uniform magnetic field and Non-uniform magnetic field?

Galina-37 [17]

Magnetic field is the magnetic effect of electric currents and magnetic materials. The magnetic field at any given point specified by both direction and a magnitude. So uniform magnetic field has equal amount of force or magnetic force in both side of the object while the non uniform magnetic field has one of the object exert more than the other

4 0

3 years ago

find the resistance of a multiplier connected with milliammeter of resistance 10 ohms with a deflection of 10 milliamperes and t

Murljashka [212]

The answer is 26 because you add

8 0

2 years ago

A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i

sergeinik [125]

Answer:

Density of unknown liquid is $2047 kg/m^3$

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

$T = mg = 43.8 N$

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

$T_1 + F_b = mg$