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xz_007 [3.2K]
3 years ago
12

Find the work done by a force of 8 pounds acting in the direction of 44° to the horizontal in moving an object 7 feet from (0, 0

) to (7, 0). Round answer to the nearest tenth of a foot-pound.
Physics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

40.3 ft-lbs

Explanation:

Work = Force•Distance = (Force)(Distance)(cosΘ)

Note what you know and/or don't know. In this case:

Force = 8lbs

Distance = 7ft

Θ = 44°

So with that and the formula of work above, we can say:

Work = (8lbs)(7ft)(cos44°) = 40.28...ft-lbs

When rounded you have 40.3 ft-lbs of work done by the force.

Side note: Just to be clear, the formula Force•Distance is said as Force "dot" Distance. It's a dot product and not just a multiplication sign; which is why the angle is important to know.

Force×Distance is said as Force "cross" Distance, which relates to a different kind of force and has a slightly different formula.

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To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg. 
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3 years ago
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Answer:

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Explanation:

a)

Given:

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We know that the change in entropy is given by:

\Delta s=\frac{dQ}{T_f-T_i}

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b)

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initial temperature of house, T_i=23.5+273=296.5\ K

final temperature of house, T_f=5.3+273=278.3\ K

\Delta s=\frac{dQ}{T_f-T_i}

\Delta s=\frac{5.8\times 10^8}{278.3-296.5}

\Delta s=31868131.8681\ J.K^{-1}

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Answer:

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Explanation:

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