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xz_007 [3.2K]
3 years ago
12

Find the work done by a force of 8 pounds acting in the direction of 44° to the horizontal in moving an object 7 feet from (0, 0

) to (7, 0). Round answer to the nearest tenth of a foot-pound.
Physics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

40.3 ft-lbs

Explanation:

Work = Force•Distance = (Force)(Distance)(cosΘ)

Note what you know and/or don't know. In this case:

Force = 8lbs

Distance = 7ft

Θ = 44°

So with that and the formula of work above, we can say:

Work = (8lbs)(7ft)(cos44°) = 40.28...ft-lbs

When rounded you have 40.3 ft-lbs of work done by the force.

Side note: Just to be clear, the formula Force•Distance is said as Force "dot" Distance. It's a dot product and not just a multiplication sign; which is why the angle is important to know.

Force×Distance is said as Force "cross" Distance, which relates to a different kind of force and has a slightly different formula.

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It's used to measure the mass or weight of an object
7 0
3 years ago
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An iron railroad rail is 800 ft long when the temperature is 31°C. What is its length (in ft) when the temperature is −17°C?
natta225 [31]

Answer:

799.54 ft

Explanation:

Linear thermal expansion is:

ΔL = α L₀ ΔT

where ΔL is the change in length,

α is the linear thermal expansion coefficient,

L₀ is the original length,

and ΔT is the change in temperature.

Given:

α = 1.2×10⁻⁵ / °C

L₀ = 800 ft

ΔT = -17°C − 31°C = -48°C

Find: ΔL

ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)

ΔL = -0.4608

Rounded to two significant figures, the change in length is -0.46 ft.

Therefore, the final length is approximately 800 ft − 0.46 ft = 799.54 ft.

7 0
3 years ago
Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i
Digiron [165]

Answer:

3.31m/s

Explanation:

Angular momentum for 3s is

L = L_i_n_i + L_3_s

L = 2(11.5kg) + \int\limits^ {3s}_ {0s} {(t^2 + 2)} \, dt

L = 23kg+(\frac{t^3}{3} +2t)^ {3s}_ {0s}\\\\L=38kgm/s

Moment if inertia is

I = 2ml^2

I = 2(11.5)(0.5)^2\\\\I=5.75kgm^2

Angular speed

ω = L/I

= 38 / 5.75\\\\=6.61

The speed of each ball is

V = ωL

= 6.61\times0.5\\\\= 3.31m/s

7 0
3 years ago
How much is a city of a body when it covers 600m in 5 min?
Fofino [41]

Answer:

2m/s

Explanation:

5min × 60sec

=300

now,

600÷300

=2

3 0
3 years ago
If a cylindrical space station 275 m in diameter is to spin about its central axis, at how many revolutions per minute (rpm) mus
sergij07 [2.7K]

The centripetal acceleration is responsible for the artificial gravity because the acceleration of an object moving in constant circular motion causing from net external force is called centripetal acceleration. It defines to the center or seeking the center.

Given the following:

Cylindrical space station diameter           = 275 meters; 137.5 meters for the radius

Standard gravity                                       = 9.80665 m/s²

 

Using the formula:

w² x r =g

w² = g / r

w² = 9.80665 m/s² / 137.5 m

w² = 9.80665 m/s² / 137.5 m

w² = 0.0713 s²

Then take the roots

w = 0.267 this is radians per second / 2 x (3.1416 which is the pi)

w = 0.0424 rps convert to rpm

w = 0.0424 r/s (1minute / 60 seconds)

w = 7.08 x 10⁻⁴ revolutions per minute

4 0
3 years ago
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