The amount of seawater that will be displaced would be 1.3274 x

<h3>Density and volume</h3>
Density = mass/volume.
Since a floating object displaces its own weight, a 4247 tons ship will also displace the same amount of water.
4247 tons of seawater = 3.8528 x
g
volume of 3.8528 x
g seawater = mass/density = 3.8528 x
g/1.025 = 3758829268.29 cubic centimeter.
3758829268.29
= 132741.80
or 1.3274 x

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From the pair of values given, the ratio of the volume to the temperature for the first data pair is, 0.0026 cm³/K
<h3>What is a Ratio?</h3>
A ratio is a comparison between two quantities showing how much one quantity differs from another.
From the data given, the first data pair is as follows ;
- Temperature = 276 K
- Volume = 0.72 cm³
Ratio of volume to temperature = volume / temperature
Ratio = 0.72 / 276
Ratio = 0.002608 cm³/K
The significant figure's rule for division is the least number of significant figures used in the operation.
The least significant figure of the values given is 2.
Therefore, the ratio of the volume to the temperature for the first data pair is 0.0026 cm³/K
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Answer:
it have 10 neutrons and it is Fluorine(F).
Using the VSPER theory, the effect of lone pairs on molecular shape can be discussed.
There are 3 types of electron pairs present in a molecular shape: bond pair -bond pair, lone pair - bond pair, lone pair - lone pair.
Strength of repulsions between these three types of pair follows the order:
lone pair- lone pair > lone pair - bond pair > bond pair - bond pair
Whenever there is an addition of lone pairs to the geometry, some distortions take place which decreases the bond angles and some asymmetry is attained in the original molecular shape.
Answer:
27 liters of hydrogen gas will be formed
Explanation:
Step 1: Data given
Number of moles C = 1.03 moles
Pressure H2 = 1.0 atm
Temperature = 319 K
Step 2: The balanced equation
C +H20 → CO + H2
Step 3: Calculate moles H2
For 1 mol C we need 1 mol H2O to produce 1 mol CO an 1 mol H2
For 1.03 moles C we'll have 1.03 moles H2
Step 4: Calculate volume H2
p*V = n*R*T
⇒with p = the pressure of the H2 gas = 1.0 atm
⇒with V = the volume of H2 gas = TO BE DETERMINED
⇒with n = the number of moles H2 gas = 1.03 moles
⇒with R = the gas constant = 0.08206 L*Atm/mol*K
⇒with T = the temperature = 319 K
V = (n*R*T)/p
V = (1.03 * 0.08206 *319) / 1
V = 27 L
27 liters of hydrogen gas will be formed