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k0ka [10]
1 year ago
15

In the coordination compound [Cr(NH3)2(en)Cl2]Br2, the coordination number (C.N.) and oxidation number (O.N.) of the metal atom,

respectively, are
Chemistry
1 answer:
erma4kov [3.2K]1 year ago
7 0

The coordination number (C.N.) is 6 and oxidation number (O.N.) is +4 of the metal atom.

C.N. = 6; O.N. = +4

<h3><u>What </u><u>is Co-ordination number ?</u></h3>
  • The coordination number, also known as ligancy, of a central atom in a molecule or crystal in chemistry, crystallography, and materials science refers to the quantity of atoms, molecules, or ions bound to it.
  • A ligand is the ion, molecule, or atom that surrounds the center ion, molecule, or atom.
  • The number of atoms, ions, or molecules that a central atom or ion in a complex, coordination compound, or crystal holds as its closest neighbors.
<h3><u>What is Oxidation number ?</u></h3>
  • The total number of electrons that an atom acquires or loses to establish a chemical connection with another atom is known as the oxidation number, also known as the oxidation state.
  • Each atom involved in an oxidation-reduction reaction has an oxidation number that represents how many electrons it may take, give, or share.

To view more questions of coordination number, refer to:

brainly.com/question/8717978?referrer=searchResults

#SPJ4

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How many kJ of heat are released by the reaction of 25.0 g of Na2O2(s) in the following reaction? (M = 78.0 g/mol for Na2O2)
solong [7]

-20.16 KJ of heat are released by the reaction of 25.0 g of Na2O2.

Explanation:

Given:

mass of Na2O2 = 25 grams

atomic mass of Na2O2 = 78 gram/mole

number of mole = \frac{mass}{atomic mass of 1 mole}

                          = \frac{25}{78}

                          =0. 32 moles

The balanced equation for the reaction:

2 Na2O2(s) + 2 H2O(l) → 4 NaOH(aq) + O2(g) ∆Hο = −126 kJ

It can be seen that 126 KJ of energy is released when 2 moles of Na2O2 undergoes reaction.

similarly 0.3 moles of Na2O2 on reaction would give:

\frac{126}{2} = \frac{x}{0.32}

x = \frac{126 x 0.32}{2}

 = -20.16 KJ

Thus, - 20.16 KJ of energy will be released.

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