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KonstantinChe [14]
3 years ago
10

write both he full balanced ionic equation for the following reaction and the balanced net ionic equation. What are the specter

ions if there are any (If not write that there are none)? a) balanced equation (1 point) b) full ionic equation (1 point) c) net ionic equation (2 points) d) spctator ions if there are any (1 point) EQUATION: AgNO3(aq) + GaCl3(aq) --> AgCL(s) + Ga (NO3)3(aq)
Chemistry
1 answer:
Nonamiya [84]3 years ago
6 0
A) 3AgNO3 + GaCl3 --> 3AgCl + Ga(NO3)3
b) 3Ag(+) + 3NO3(-) + Ga(3+) + 3Cl(-) --> 3AgCl(s) + Ga(3+) + 3NO3(-)
c) 3Ag(+) + 3Cl(-) --> 3AgCl(s)
d) Ga(3+), 3NO3(-)
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If parents wanted to pick their child's traits like hair color, gender, eye color, what would doctors have to do?
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Answer:

Nothing

Explanation:

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How many elements does a compound need to form?
Vinvika [58]

Answer:

two

Explanation:

When two distinct elements are chemically combined, chemical bonds form between their atoms. the result is called a chemical compound

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What is the volume of a liquid that has a density 3.65g/ml and a mass of 5.61g
Lorico [155]

Answer:

<h2>1.54 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{5.61}{3.65}  \\  =1.536986...

We have the final answer as

<h3>1.54 mL</h3>

Hope this helps you

3 0
3 years ago
In a process for producing acetic acid, oxygen gas is bubbled into acetaldehyde, CH3CHO, containing manganese(II) acetate (catal
grigory [225]

<u>Answer:</u> The mass of acetic acid that can be produced is 30.24 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For acetaldehyde:</u>

Given mass of acetaldehyde = 22.2 g

Molar mass of acetaldehyde = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of acetaldehyde}=\frac{22.2g}{44g/mol}=0.504mol

  • <u>For oxygen gas:</u>

Given mass of oxygen  gas = 12.6 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{12.6g}{32g/mol}=0.394mol

The given chemical equation follows:

2CH_3CHO(l)+O_2(g)\rightarrow 2CH_3COOH(l)

By Stoichiometry of the reaction:

2 moles of acetaldehyde reacts with 1 mole of oxygen gas

So, 0.504 moles of acetaldehyde will react with = \frac{1}{2}\times 0.504=0.252mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, acetaldehyde is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of acetaldehyde produces 2 moles of acetic acid

So, 0.504 moles of acetaldehyde will produce = \frac{2}{2}\times 0.504=0.504moles of acetic acid

Now, calculating the mass of acetic acid from equation 1, we get:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.504 moles

Putting values in equation 1, we get:

0.504mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.504mol\times 60g/mol)=30.24g

Hence, the mass of acetic acid that can be produced is 30.24 grams

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Read the following chemical equations.
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