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marishachu [46]
2 years ago
13

The following balanced equation shows the formation of water.

Chemistry
1 answer:
Elanso [62]2 years ago
7 0

The number of moles of oxygen (O2) required to completely react with 27.4 mol of H2 is 13.7 moles.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated using stoichiometry as follows:

The following balanced chemical equation is given as follows:

2H2 + O2 = 2H2O

According to this question, 2 moles of hydrogen gas (H2) reacts with 1 mole of oxygen gas (O2).

This means that 27.4 moles of hydrogen gas (H2) will react with 27.4/2 = 13.7moles of oxygen gas.

Therefore, the number of moles of oxygen (O2) required to completely react with 27.4 mol of H2 is 13.7 moles.

Learn more about number of moles at: brainly.com/question/14919968

#SPJ1

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Hydrogen produced from a hydrolysis reaction was collected over water and the following data was compiled.
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  • 0.00358 mol

Explanation:

<u>1) Data:</u>

a) V = 93.90 ml

b) T = 28°C

c) P₁ = 744 mmHg

d) P₂ = 28.25 mmHg

d) n = ?

<u>2) Conversion of units</u>

a) V = 93.90 ml × 1.000 liter / 1,000 ml = 0.09390 liter

b) T = 28°C = 28 + 273.15 K = 301.15 K

c) P₁ = 744 mmHg × 1 atm / 760 mmHg = 0.9789 atm

d) P₂ = 28.5 mmHg × 1 atm / 760 mmHg = 0.0375 atm

<u>3) Chemical principles and formulae</u>

a) The total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas. Hence, the partical pressure of the hydrogen gas collected is equal to the total pressure less the vapor pressure of water.

b) Ideal gas equation: pV = nRT

<u>4) Solution:</u>

a) Partial pressure of hydrogen gas: 0.9789 atm - 0.0375 atm = 0.9414 atm

b) Moles of hygrogen gas:

pV = nRT ⇒ n = pV / (RT) =

n =  (0.9414 atm × 0.09390 liter) / (0.0821 atm-liter /K-mol × 301.15K) =

n = 0.00358 mol (which is rounded to 3 significant figures) ← answer

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