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mote1985 [20]
1 year ago
15

Give three examples of objects in equilibrium found in classroom?​

Physics
1 answer:
Charra [1.4K]1 year ago
7 0

Answer:

Book. Bottle. table are some examples of objects in equilibrium found in classroom

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The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2
Oliga [24]

Answer:

The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which coefficients would be placed in front of water and oxygen?

2 in front of water and 1 in front of oxygen

Kiley wants to balance the equation H2 + N2 → NH3. Which would be her first step in balancing an equation?

NOT adding the coefficient 3 in front of H2 and the coefficient 2 in front of NH3

Which is the balanced equation for V2O5 + CaS → CaO + V2S5?

V2O5 + 5CaS → 5CaO + V2S5

One half of a balanced chemical equation is shown.

3Mg(OH)2 + 2H3PO4

Which lists the numbers of each atom the other half of the equation would contain?

3 Mg, 2 P, 14 O, 12 H

Substances A and B react in a ratio of A + B → AB. Colin was combining substance A and substance B to form substance AB. He added 10 g of substance A and 45 g of substance B.

How much of substance AB would Colin make?

55g

Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting equation?

NOT 2C4H3Br + 5O2 → 4CO2 + 2H2O + 2HBr

NOT C4H3Br + O2 → CO2 + H2O + HBr

Which best describes the law of conservation of mass?

The mass of the reactants and products is equal and is not dependent on the physical state of the substances.

6 0
3 years ago
Read 2 more answers
A car with a mass of 650 kg is moving with a speed of 20m/s. Calculate the kinetic energy of the car?
tatuchka [14]
KE=1/2MV2
So 1/2(650)(20)squared
1/2(650)(400)
200(650)
130,000 J
8 0
3 years ago
What are two ways you can change atomic mass
e-lub [12.9K]
Atomic mass can change through the process of fusion. Another way is, it can also change in nuclear fusion.
4 0
3 years ago
A tuning fork with a frequency of 335 Hz and a tuning fork of unknown frequency produce beats with a frequency of 5.3 when struc
Ganezh [65]

Answer:

Explanation:

Unknown fork frequency is either

335 + 5.3 = 340.3 Hz

or

335 - 5.3 = 329.7 Hz

After we modify the known fork, the unknown fork frequency equation becomes either

(335 - x) + 8 = 340.3

(335 - x)  = 332.3

x = 2.7 Hz

or

(335 - x) + 8 = 329.7

(335 - x) = 321.7

x = 13.3 Hz

IF the unknown fork frequency was 340.3 Hz,

THEN the 335 Hz fork was detuned to 335 - 2.7 = 332.3 Hz

IF the unknown fork frequency was 329.7 Hz,

THEN the 335 Hz fork was detuned to 335 - 13.3 = 321.7 Hz

3 0
2 years ago
Difference between of echo and reverberation​
KiRa [710]

Answer:

A difference between of echo and reverberation​  is described below in details.

Explanation:

Here's a piece of immediate information: An echo is an individual consideration of a soundwave off a horizon exterior. Reverberation is the consideration of sound waves generated by the superposition of the before-mentioned echoes. ... A reverberation can happen when a sound wave is displayed off a nearby covering.

5 0
3 years ago
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