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Elina [12.6K]
2 years ago
9

A toaster with a power rating of 1,000 watts is plugged into a household voltage of 120 volts. How much current runs through the

toaster?
A) 120,000 amps
B) 880 amps
C) 8.3 amps
D) 0.120 amps
Physics
2 answers:
deff fn [24]2 years ago
6 0

Answer : I = 8.33 A

Explanation :

It is given that,

Power rating of the toaster, P = 1000 watts

Household voltage, V = 120 volts

We know the relation between power, voltage and the current is :

P=V\times I

I=\dfrac{P}{V}

I=\dfrac{1000\ W}{120\ V}

I = 8.33\ A

8.33 A of current runs through the toaster.

Hence, this is the required solution.

Lunna [17]2 years ago
4 0
C) 8.3 i believe i wouldnt take me 100%
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The gravitational potential energy (G.P.E) of the ceiling fan is 712.95 Joules.

<u>Given the following data:</u>

  • Mass of ceiling fan = 7.5 kg
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<u>Scientific data:</u>

  • Acceleration due to gravity = 9.8 m/s^2

To calculate the gravitational potential energy (G.P.E) of the ceiling fan:

<h3>What is gravitational potential energy?</h3>

Gravitational potential energy (G.P.E) can be defined as the energy that is possessed by an object or body due to its position (height) above planet Earth.

Mathematically, gravitational potential energy (G.P.E) is given by this formula;

GPE = mgh

<u>Where:</u>

  • G.P.E is the gravitational potential energy.
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  • g is the acceleration due to gravity.
  • h is the height of an object.

Substituting the given parameters into the formula, we have;

GPE = 7.5 \times 9.8 \times 9.7

GPE = 712.95 Joules.

Read more on potential energy here: brainly.com/question/8664733

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How are these ions distinguished from one another in writing formulas for compounds? A. using Latin prefixes B. using numerical
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B. using numerical superscripts

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When writing the symbol for an ion, the one- or two-letter element symbol is written first, followed by a superscript. The superscript has the number of charges on the ion followed by a + (for positive ions or cations) or - (for negative ions or anions). Neutral atoms have a charge of zero, so no superscript is given.

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For an object of mass M, that is at a distance H from the ground, the potential energy can be written as:

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In this case, we have that:

mass of the weights = 1,250 kg

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Then the potential energy of the weights is:

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