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melisa1 [442]
3 years ago
6

PLEASE HELP!! I WILL MARK BRAINLIST

Physics
1 answer:
Stella [2.4K]3 years ago
3 0

sound wave amplitude

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Newton's first law of motion is sometimes called the law of _________.
Gre4nikov [31]
Newtons first law of motion is also known as the law of inertia
3 0
3 years ago
A 15.0-μF capacitor is charged by a 130.0-V power supply, then disconnected from the power and connected in series with a 0.280-
SVETLANKA909090 [29]

The resonant frequency of a circuit is the frequency \omega_0 at which the equivalent impedance of a circuit is purely real (the imaginary part is null).

Mathematically this frequency is described as

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

Where

L = Inductance

C = Capacitance

Our values are given as

C = 15*10^{-6}\mu F

L = 0.280*10^{-3}mH

Replacing we have,

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

f = \frac{1}{2\pi}(\sqrt{\frac{1}{(15*10^{-6})(0.280*10^{-3})}})

f= 2455.81Hz

From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.

For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.

7 0
3 years ago
PLZ HELP IM REALLY CONFUSED a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, the
erastovalidia [21]

Answer:

K.E = 100 J

Final P.E = 100 J

Explanation:

The kinetic energy of any object can be given by the following formula:

K.E = (\frac{1}{2})mv^{2}

where,

K.E = Kinetic Energy

m = mass of ball = 2 kg

v = speed of ball

Initially, v = 10 m/s. Therefore, the initial K.E is given as:

K.E = (\frac{1}{2})(2\ kg)(10\ m/s)^{2}

<u>K.E = 100 J</u>

Now, at the highest point the K.E of the ball becomes zero. because the ball stops for a moment at the highest point and its velocity becomes zero. So, from Law of Conservation of energy:

Initial K.E + Initial P.E = Final K.E + Final P.E

Initial P.E is also zero due to zero height initially.

K.E + 0 = 0 + Final P.E

<u>Final P.E = 100 J</u>

3 0
3 years ago
Josh is refilling his pool with clean water. How many gallons of water will it take if the pool is 50m by 25m by 1.5m?
horsena [70]

Answer:

V = 493421.05 [gal]

Explanation:

This is a problem that consists of handling units, we can calculate by first-hand the volume, then convert units from cubic meters to gallons.

V = 50 * 25 * 1.5

V = 1875 [m^3]

Now we need to convert units, using the proper conversion factor.

1875[m^3]*\frac{1000lt}{1m^3} *\frac{1gal}{3.8lt} \\493421.05[gal]

7 0
4 years ago
A car traveling at +1.5 m/s accelerates at the rate of 0.65 m/s for an interval of 2.6a find vf
mario62 [17]

Vf ( final velocity) = ?

Vo ( initial velocity) = 1.5 m/s

a (acceleration) = .65 m/s^2

t (time) = 2.6 seconds

The equation you want is Vf = Vo + (a)(t).

Plugging in the variables gives Vf = 1.5 + (.65)(2.6).

The final velocity is 1.5 + 1.69, which comes out to +3.19 m/s.

5 0
3 years ago
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