Answer:
Explanation:
We have a metal ring of diameter
d = 4.2cm = 0.042m
r = d/2 = 0.021m
And it is place between the north pole and south pole of a large magnet with the plane of it's area perpendicular to the magnetic field.
Given that the magnetic field is
B = 1.12 T
The rate of decrease of magnetic field is 0.2T/s, since it is decrease then,
dB/dt = -0.2 T/s
The induce electric field is given as,
From faradays law
ε = ∫E•dl = -dΦ/dt
Magnetic flux is given as
Φ = BA
Φ = πr²×B = πr²B
Also, ∫E•dl = E×2πr = 2πrE
So,
∫E•dl = -dΦ/dt
2πrE = -d(πr²B) / dt
r is a constant, then
2πrE = -πr² dB/dt
Divide both side by πr
2E = -r dB/dt
E = -r dB/dt / 2
E = -0.021 × -0.2 / 2
E = 0.0021 V/m
The magnetic field point from north to south pole and it is decreasing and this means that the magnetic flux is also decreasing, so the induce magnetic field must point in the same direction of the original magnetic field, so the induce current circulate counter-clockwise as viewed from the south pole
Answer:
B
Explanation:
Given:-
- The charge of the test particle q = 3.0 * 10^-9 C
- The force exerted by the metal sphere F = 6.0 * 10^-5 N
Find:-
The magnitude and direction of the electric field
strength at this location?
Solution:-
- The relationship between the electrostatic force F exerted by the metal sphere on the test-charge and the Electric Field strength E at the position of test charge is given by:
F = E*q
- Using the data given we can determine E:
E = F / q
E = (6.0 * 10^-5) / (3.0 * 10^-9)
E = 20,000 N/C
- The direction of electric field is given by the net charge of the source ( metal sphere). The metal sphere is negative charge hence the direction of Electric Field strength E is directed towards the metal sphere.
Answer:
6.3445×10⁻¹⁶ m
Explanation:
E = Accelerating voltage = 2.47×10³ V
m = Mass of electron
Distance electron travels = 33.5 cm = 0.335 cm
Deflection by Earth's Gravity
Now, Time = Distance/Velocity
∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m
True. No matter can be created nor destroyed in pretty much every aspect of life, especially chemical reactions.
Energy of a wave:
E = nhc/λ
3000 = (n x 6.63 x 10⁻³⁴ x 3 x 10⁸)/(510 x 10⁻⁹)
n = 7.69 x 10 ²¹ photons per second per meter²
2.70 cm² = 2.70/10,000 m²
= 2.7 x 10⁻⁴
Photons per second = 7.69 x 10 ²¹ x 2.7 x 10⁻⁴
= 2.08 x 10¹⁸ photons per second
