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3 years ago

How does the search for exoplanets help us describe how science requires creativity?

Physics

1 answer:

Aliun [14]3 years ago

5 0

Answer:

As the planets are very small and dark in comparison with stars, it makes them very hard to be found from earth.

Explanation:

Astronomy, of course, has a solution for this. As astronomers can't observe planets directly, they decided to observe the stars and search for the effects that planets have on them.

There are many ways of observing the exoplanets: Radial Velocity, Transit Photometry, Microlensing, Astrometry, Direct Imaging, etc.

Before all of this, scientist had to find ways to prove their theories. Most of their time they have spent in giving the creative answers.

Science and creativity are very much connected when we speak about the development of science. Rationality and creativity always go together.

In order to create an idea that other people will consider useful, it is important to use creativity. As no one has the exact answer when it comes to science, the adventure is to research the unknown.

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Exoplanets (planets outside our solar system) are an active area of modern research. Suppose astronomers find such a planet that

Leno4ka [110]

Answer:

8.829 m/s²

Explanation:

M = Mass of Earth

m = Mass of Exoplanet

$g_e$ = Acceleration due to gravity on Earth = 9.81 m/s²

g = Acceleration due to gravity on Exoplanet

$m=M-0.1M\\\Rightarrow m=0.9M$

$g_e=G\frac{M}{r^2}$

$g=G\frac{0.9M}{r^2}$

Dividing the equations we get

$\frac{g}{g_e}=\frac{G\frac{0.9M}{r^2}}{G\frac{M}{r^2}}\\\Rightarrow \frac{g}{g_e}=0.9\\\Rightarrow g=0.9g_e\\\Rightarrow g=0.9\times 9.81\\\Rightarrow g=8.829\ m/s^2$

Acceleration due to gravity on the surface of the Exoplanet is 8.829 m/s²

3 0

4 years ago

This is the science of extremely small structures and is leading to advanced materials, devices and applications in energy, medi

miv72 [106K]

Answer:

Nanotechnology

Explanation:

is this for that crossword puzzle lol

3 0

4 years ago

7. The S.l. unit for force is<br> A. kg<br> C. m/s<br> B. m/s2<br> D. N

netineya [11]

D.N(Newton) this is the S.I unit for force

5 0

3 years ago

Noelle walks from point A to point B at an average speed of 5 kilometers per hour. At what speed, in kilometers per hour, must N

Debora [2.8K]

Answer:

the speed at which Noelle walks from point B to A, v=7.5 kilometers per hour

Explanation:

In this question we have given

average speed for the entire trip,S = 6 kilometers per hour

Speed of Noelle while walks from point A to B= 5 kilometers per hour

Therefore, time taken by Noelle to walks from point A to B, $t_{1}=\frac{d}{5}$

Let us consider distance between A and B is d.

Therefore total distance covered in moving from point A to B and then moving back from point B to A, = $d+d=2d$

Let v be the speed at which Noelle walks from point B to A

Therefore time taken by Noelle to walks from point B to A, $t_{2}=\frac{d}{v}$

we know that average speed S is given as

$S=\frac{x}{t}$ ................(1)

here, x (=2d) is total distance

and t (= $t_{1}+t_{2}$ ) is total time

put values of S, x and t in equation 1

$6 =\frac{2d}{\frac{d}{5}+\frac{d}{v} }$

on solving we get,

v = 7.5 kilometers per hour

Therefore, the speed at which Noelle walks from point B to A, v=7.5 kilometers per hour

5 0

3 years ago

Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i

Troyanec [42]

Answer:

73.52983 Hp

Explanation:

m = Mass of car = $\dfrac{W}{g}$

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

$v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}$

From the question

$F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N$

Balancing the forces

$\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp$

The power is 73.52983 Hp

6 0

4 years ago