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nadya68 [22]
4 years ago
14

A light bulb, a fan, and a tiny speaker are connected to a battery in a series circuit. How will the circuit behave if it is ope

n?
A) None of the devices will work.
B) The battery will heat up and explode.
C) Only the device closest to the battery will work.
D) The bulb will light, the fan will blow, and the speaker will make noise.
Physics
1 answer:
gtnhenbr [62]4 years ago
7 0

Answer:

a

Explanation:

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When light of wavelength 240 nm falls on a potassium surface, electrons having a maximum kinetic energy of 2.93 eV are emitted.
olchik [2.2K]

A) We want to find the work function of the potassium. Apply this equation:

E = 1243/λ - Φ

E = energy of photoelectron, λ = incoming light wavelength, Φ = potassium work function

Given values:

E = 2.93eV, λ = 240nm

Plug in and solve for Φ:

2.93 = 1243/240 - Φ

Φ = 2.25eV

B) We want to find the threshold wavelength, i.e. find the wavelength such that the energy E of the photoelectrons is 0eV. Plug in E = 0eV and Φ = 2.25eV and solve for the threshold wavelength λ:

E = 1243/λ - Φ

0 = 1243/λ - Φ

0 = 1243/λ - 2.25

λ = 552nm

C) We want to find the frequency associated with the threshold wavelength. Apply this equation:

c = fλ

c = speed of light in a vacuum, f = frequency, λ = wavelength

Given values:

c = 3×10⁸m/s, λ = 5.52×10⁻⁷m

Plug in and solve for f:

3×10⁸ = f(5.52×10⁻⁷)

f = 5.43×10¹⁴Hz

7 0
4 years ago
QUESTION 5
liberstina [14]

Answer:

0.69 g/cm^3

Explanation:

Given that a small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79mL.

The volume of the frog will be:

79 - 50 = 29mL

Convert it to litre by dividing it by 1000

29/1000 = 0.029 L

Since 1L = 1000 cm^3

Convert it to cm^3 by multiplying it by 1000

0.029 × 1000 = 29 cm^3

Density = mass/volume

Substitute the mass and volume into the formula

Density = 20/29

Density = 0.6896 g/cm3

Therefore, the density of the frog is 0.69 g/cm^3 approximately

5 0
3 years ago
fins the powee of a convex lens which forms a real and inverted image of magnification -1 of an object placed at a distance from
anzhelika [568]

Explanation:

hope i am correct

hii

how are you

7 0
3 years ago
A simple harmonic oscillator completes 1550 cycles in 30 min. (a) Calculate the period. s (b) Calculate the frequency of the mot
nordsb [41]

Answer:

(a) 1.16 s

(b)0.861 Hz

Explanation:

(a) Period : The period of a simple harmonic motion is the time in seconds, required for a object undergoing oscillation to complete one cycle.

From the question,

If 1550 cycles is completed in (30×60) seconds,

1 cycle is completed in x seconds

x = 30×60/1550

x = 1.16 s

Hence the period is 1.16 seconds.

(b) Frequency : This can be defined as the number of cycles that is completed in one seconds, by an oscillating body. The S.I unit of frequency is Hertz (Hz).

Mathematically, Frequency is given as

F = 1/T ........................... Equation 1

Where F = frequency, T = period.

Given: T = 1.16 s.

Substitute into equation 1

F = 1/1.16

F = 0.862 Hz

Hence thee frequency = 0.862 Hz

6 0
4 years ago
Which of the following is a contact force?
shusha [124]

hope this helps.........

7 0
3 years ago
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