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nadya68 [22]
4 years ago
14

A light bulb, a fan, and a tiny speaker are connected to a battery in a series circuit. How will the circuit behave if it is ope

n?
A) None of the devices will work.
B) The battery will heat up and explode.
C) Only the device closest to the battery will work.
D) The bulb will light, the fan will blow, and the speaker will make noise.
Physics
1 answer:
gtnhenbr [62]4 years ago
7 0

Answer:

a

Explanation:

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Why measurement standards are necessary
ivanzaharov [21]

Answer:

standard unit of measurement provides a reference point by which objects of weight, length or capacity can be described.

6 0
4 years ago
List any similarities between discovered exoplanets and planets in our solar system.
gregori [183]

Answer:

1. Revolve around a point

2. Formed from dust and gas particles

3. Exoplanets and associated star orbit a common center of mass  

4. Composed of gases found in Jupiter and Saturn

3 0
3 years ago
Three resistors, 6.0-W, 9.0-W, 15-W, are connected in parallel in a circuit. What is the equivalent resistance of this combinati
ycow [4]

Answer:

2.9Ω

Explanation:

Resistors are said to be in parallel when they are arranged side by side such that their corresponding ends are joined together at two common junctions. The combined resistance in such arrangement of resistors is given by;

1/Req= 1/R1 + 1/R2 + 1/R3 .........+ 1/Rn

Where;

Req refers to the equivalent resistance and R1, R2, R3 .......Rn refers to resistance of individual resistors connected in parallel.

Note that;

R1= 6.0Ω

R2 = 9.0Ω

R3= 15.0 Ω

Therefore;

1/Req = 1/6 + 1/9 + 1/15

1/Req= 0.167 + 0.11 + 0.067

1/Req= 0.344

Req= (0.344)^-1

Req= 2.9Ω

3 0
3 years ago
A bowling ball has a mass of 5 kg. A student rolls the bowling ball one time at 1 m/s and a second time and 2 m/s. Compare the m
sasho [114]
The answer is 5kg m/s with the second momentum being 10 kg m/s. i took the test and it was right. hope this helps yalls
5 0
3 years ago
A small laser used as a pointer produces a beam of red light 5 mm in diameter, and has a power output of 5 milliwatts. What is t
Nata [24]

Answer:

434.0 V/m

Explanation:

The power output of the laser is:

P=5 mW = 0.005 W

while the radius of the beam is

r=\frac{5 mm}{2}=2.5 mm = 0.0025 m

so the cross-sectional area is

A=\pi r^2 = \pi (0.0025 m)^2=2.0\cdot 10^{-5} m^2

So the intensity of the laser beam is

I=\frac{P}{A}=\frac{0.005 W}{2.0\cdot 10^{-5} m^2}=250 W/m^2

The intensity of a laser beam is related to the magnitude of the electric field by

I=\frac{1}{2}c\epsilon_0 E^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

Solving the formula for E, we find

E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(250 W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=434.0 V/m

4 0
3 years ago
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