Aaron leaves one city at noon. He has to be at another city 186km away at 3:00p.m. The speed limit the entire way is 65 km/h. Ca
2 answers:
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Answer:
a) The work required to stretch the spring from 20 centimeters to 25 centimeters is 0.313 joules, b) The area of the region enclosed by one loop of the curve is
.
Explanation:
a) The work, measured in joules, is a physical variable represented by the following integral:
Where
,
- Initial and final position, respectively, measured in meters.
- Force as a function of position, measured in newtons.
Given that and the fact that
when
, the spring constant (
), measured in newtons per meter, is:
Now, the work function is obtained:
The work required to stretch the spring from 20 centimeters to 25 centimeters is 0.313 joules.
b) Let be . The area of the region enclosed by one loop of the curve is given by the following integral:
By using trigonometrical identities, the integral is further simplified:
The area of the region enclosed by one loop of the curve is
.
Answer:
Explanation:
From the question we are told that:
Crane Length
Crane Mass
Arm extension at lifting end
Arm extension at counter weight end
Load
Generally the equation for Torque Balance is mathematically given by
Answer:
8.94*10^22 kg
Explanation:
Given that
Mass of Lo, M = ?
Radius of Lo, r = 1.82*10^6 m
Acceleration on Lo, g = 1.80 m/s²
Gravitational constant, G = 6.67*10^-11
Using the formula
g = GM/r²
Solution is attached below
Answer is 8.94*10^22 kg
