The work done by force on a spring hung from the ceiling will be 1.67 J
Any two things with mass are drawn together by the gravitational pull. We refer to the gravitational force as attractive because it consistently seeks to draw masses together rather than pushing them apart.
Given that a spring is hung from the ceiling with a 2.0-kg mass suspended hung from the spring extends it by 6.0 cm and a downward external force applied to the mass extends the spring an additional 10 cm.
We need to find the work done by the force
Given mass is of 2 kg
So let,
F = 2 kg
x = 0.1 m
Stiffness of spring = k = F/x
k = 20/0.006 = 333 n/m
Now the formula to find the work done by force will be as follow:
Workdone = W = 0.5kx²
W = 0.5 x 333 x 0.1²
W = 1.67 J
Hence the work done by force on a spring hung from the ceiling will be 1.67 J
Learn more about force here:
brainly.com/question/12970081
#SPJ4
Mostly GPE and a little KE since the ball is high up (GPE) and it's also moving (KE) but not as much as it had when you first threw it
Answer:
Mass = 1133.33 kg (Approx.)
Explanation:
Given:
Momentum = 2.04 x 10⁴ kg[m/s]
Velocity = 18 m/s
Find:
Mass
Computation:
Mass = Momentum / Velocity
Mass = [2.04 x 10⁴] / 18
Mass = 1133.33 kg (Approx.)
Answer:
The new intensity decreases by a factor of 16.
Explanation:
The intensity of sound wave is given by :

P is power
A is area

or
, r is distance from the source
If the distance from the source is increased by a factor of 4, r' = 4r
So,

So, the new intensity decreases by a factor of 16.