You always adjust numbers and it will be before the element
so you Neva add or change a subscript
Answer: There are 0.5 grams of barium sulfate are present in 250 of 2.0 M
solution.
Explanation:
Given: Molarity of solution = 2.0 M
Volume of solution = 250 mL
Convert mL int L as follows.

Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given
solution is as follows.

Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M
solution.
Answer : The complete question is attached in answer.
The value of K will be = 2 X
Explanation : We can use the formula as;
∆G = -RT ln K
on rearranging we get, K = 
Therefore, we get,
∆G/RT = (26.81 kJ/mol ) / (0.008314 kJ/mol-K) X (298K) = 10.82
So, K = 
Therefore, K = 2 X 