Answer:
sorry I've never took in this class before I will not be able to help you
Answer:
% of water boils away= 12.64 %
Explanation:
given,
volume of block = 50 cm³ removed from temperature of furnace = 800°C
mass of water = 200 mL = 200 g
temperature of water = 20° C
the density of iron = 7.874 g/cm³ ,
so the mass of iron(m₁) = density × volume = 7.874 × 50 g = 393.7 g
the specific heat of iron C₁ = 0.450 J/g⁰C
the specific heat of water Cw= 4.18 J/g⁰C
latent heat of vaporization of water is L_v = 2260 k J/kg = 2260 J/g
loss of heat from iron is equal to the gain of heat for the water


m₂ = 25.28 g
25.28 water will be vaporized
% of water boils away =
% of water boils away= 12.64 %
Answer:
Explanation:
Given the following data;
Initial volume = 2.5 L
Initial temperature = 350 K
Final volume = 2V1 = 2*2.5 = 5 L
To find the final temperature, we would use Charles law;