Answer:
0.006075Joules
Explanation:
The final kinetic energy of the system is expressed as;
KE = 1/2(m1+m2)v²
m1 and m2 are the masses of the two bodies
v is the final velocity of the bodies after collision
get the final velocity using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
0.12(0.45) + 0/12(0) = (0.12+0.12)v
0.054 = 0.24v
v = 0.054/0.24
v = 0.225m/s
Get the final kinetic energy;
KE = 1/2(m1+m2)v
KE = 1/2(0.12+0.12)(0.225)²
KE = 1/2(0.24)(0.050625)
KE = 0.12*0.050625
KE = 0.006075Joules
Hence the final kinetic energy of the system is 0.006075Joules
Answer:
The distance traveled by the woman is 34.1m
Explanation:
Given
The initial height of the cliff
yo = 45m final, positition y = 0m bottom of the cliff
y = yo + ut -1/2gt²
u = 20.0m/s initial speed
g = 9.80m/s²
0 = 45.0 + 20×t –1/2×9.8×t²
0 = 45 +20t –4.9t²
Solving quadratically or by using a calculator,
t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s
So this is the total time it takes for the ball to reach the ground from the height it was thrown.
The distance traveled by the woman is
s = vt
Given the speed of the woman v = 6.00m/s
Therefore
s = 6.00×5.69 = 34.14m
Approximately 34.1m to 3 significant figures.
Answer:
n1 sin θ1 = n2 sin θ2 Snell's Law (θ1 is the angle of incidence)
sin θ2 = n1 / n2 * sin θ1
sin θ2 = 2.4 / 1.33 * sin θ1
sin θ2 = 1.80 * .407 = .734
θ2 = 47.2 deg
As per Bernuolli's Theorem total energy per unit mass is given as
![\frac{P}{\rho} + \frac{1}{2}v^2 + gH = E](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7B%5Crho%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7Dv%5E2%20%2B%20gH%20%3D%20E)
now from above equation
![P = 4390 N/m^2](https://tex.z-dn.net/?f=P%20%3D%204390%20N%2Fm%5E2)
![\rho = 0.999 * 10^3](https://tex.z-dn.net/?f=%5Crho%20%3D%200.999%20%2A%2010%5E3)
![v = 7.22 * 10^{-4} m/s](https://tex.z-dn.net/?f=v%20%3D%207.22%20%2A%2010%5E%7B-4%7D%20m%2Fs)
![H = 23.6 m](https://tex.z-dn.net/?f=H%20%3D%2023.6%20m)
now by above equation
![\frac{4390}{0.999*10^3} + \frac{1}{2}*(7.22*10^{-4})^2 + 9.8*23.6 = E](https://tex.z-dn.net/?f=%5Cfrac%7B4390%7D%7B0.999%2A10%5E3%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2A%287.22%2A10%5E%7B-4%7D%29%5E2%20%2B%209.8%2A23.6%20%3D%20E)
![E = 235.7 J/kg](https://tex.z-dn.net/?f=E%20%3D%20235.7%20J%2Fkg)
Part B)
Now energy per unit weight
![U = \frac{E}{g}](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7BE%7D%7Bg%7D)
![U = \frac{235.7}{9.8}](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B235.7%7D%7B9.8%7D)
![U = 24 m](https://tex.z-dn.net/?f=U%20%3D%2024%20m)
Answer:
velocity
Explanation:
I think i dont really know