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weqwewe [10]
3 years ago
14

In which situation is the acceleration of the car negative?

Physics
2 answers:
Schach [20]3 years ago
6 0
B) The velocity of a car reduced from 50 km/h to 35 km/h over one minute
olga_2 [115]3 years ago
5 0
The most appropriate answer is B !!

as the velocity of car is decreased in one min, from 50 to 35 , so there must be deacceleration !! or say negative acceleration !!

so your answer is B !!
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How can a magnetic field be produced, using a wire, a battery, and and a nail?
Aleks [24]
It is fairly easy to build an electromagnet. All you need to do is wrap some insulated copper wire around an iron core. If you attach a battery to the wire, an electric current will begin to flow and the iron core will become magnetized. When the battery is disconnected, the iron core will lose its magnetism. Follow these steps.
Step 1 - Gather the Materials
One iron nail fifteen centimeters (6 in) long
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5 0
3 years ago
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Ph11_UnitPacket2019
frozen [14]

Let's see

Use snells law

\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}

\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}

\\ \rm\Rrightarrow \mu=0.5/0.34

\\ \rm\Rrightarrow \mu=1.47

It may be glass

3 0
2 years ago
Consider the four quantum numbers of an electron in an atom, n, l, ml, and ms. The energy of an electron in an isolated atom dep
Effectus [21]

Answer:

The energy of an electron in an isolated atom depends on b. n only.

Explanation:

The quantum number n, known as the principal quantum number represents the relative overall energy of each orbital.

The sets of orbitals with the same n value are often referred to as an electron shell, in an isolated atom all electrons in a subshell have exactly the same level of energy.

The principal quantum number comes from the solution of the Schrödinger wave equation, which describes energy in eigenstates E_n, and for the case of an hydrogen atom we have:

E_n=-\cfrac{13.6}{n^2}\, eV

Thus for each value of n we can describe the orbital and the energy corresponding to each electron on such orbital.

6 0
3 years ago
The density of mobile electrons in copper metal is 8.4 1028 m-3. Suppose that i = 4.6 1018 electrons/s are drifting through a co
Vesna [10]

Answer:

The time is 106.7 minute.

Explanation:

Given that,

Density = 8.4\times10^{28}\ m^3

Current i = 4.6\times10^{18}\ electron/s

Diameter of wire = 1.2 mm

Length = 31 cm

We need to calculate the drift velocity

Using formula of drift velocity

v_{d}=\dfrac{I}{neA}

v_{d}=\dfrac{Ne}{tne\times\pi r^2}

Put the value into the formula

v_{d}=\dfrac{4.6\times10^{18}}{8.4\times10^{28}\times\pi\times(0.6\times10^{-3})^2}

v_{d}=4.842\times10^{-5}\ m/s

We need to calculate the time

Using formula for time

v_{d}=\dfrac{l}{t}

t=\dfrac{l}{v_{d}}

Where, l = length

v_{d} = drift velocity

Put the value into the formula

t=\dfrac{31\times10^{-2}}{4.842\times10^{-5}}

t=6402.31\ sec

t=106.7\ minute

Hence, The time is 106.7 minute.

7 0
3 years ago
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