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Grace [21]
2 years ago
14

Guillermo has decided that he wants to be healthier, so he starts jogging. he has been at it for a week, but he is getting frust

rated because he cannot run very far without getting out of breath. he is beginning to think that this is not a good exercise for him since he is not very good at it. what best explains why guillermo is struggling?
Physics
1 answer:
Mashutka [201]2 years ago
7 0

He does not have much endurance since he is new to exercise. This explains best why Guillermo is struggling.

<h3>What is Endurance?</h3>
  • An organism's capacity to exert itself and remain active for a prolonged period of time, as well as its capacity to resist, withstand, recover from, and have immunity to trauma, wounds, or exhaustion, are all examples of endurance (also related to sufferance, resilience, constitution, fortitude, and hardiness). Usually, it is employed in anaerobic or aerobic exercise.
  • Depending on the type of activity, "long" can mean anything from minutes for high-intensity anaerobic exercise to hours or days for low-intensity aerobic exercise.
  • Unless a person additionally engages in resistance training to offset this effect, training for endurance can impair the ability to exert endurance strength.

To know more about endurance with the given link

brainly.com/question/1303431

#SPJ4

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How large a force is necessary to stretch a 4.0-mm-diameter steel wire from its original length by 1.0%?
jekas [21]

The force needed to stretch the steel wire by 1% is 25,140 N.

The given parameters include;

  • diameter of the steel, d = 4 mm
  • the radius of the wire, r = 2mm = 0.002 m
  • original length of the wire, L₁
  • final length of the wire, L₂ = 1.01 x L₁ (increase of 1% = 101%)
  • extension of the wire e = L₂ - L₁ = 1.01L₁ - L₁ = 0.01L₁
  • the Youngs modulus of steel, E = 200 Gpa

The area of the steel wire is calculated as follows;

A = \pi r^2\\\\ A= 3.142 \times (0.002)^2\\\\ A= 1.257 \times 10^{-5} \ m^2

The force needed to stretch the wire is calculated from Youngs modulus of elasticity given as;

E = \frac{stress}{strain} = \frac{F/A}{e/L} = \frac{FL}{Ae} \\\\F = \frac{EAe}{L}

F = \frac{200 \times 10^9\  \times\  1.257\times 10^{-5}\  \times \ 0.01l_1}{l_1} \\\\F = 25,140\ N

Thus, the force needed to stretch the steel wire by 1% is 25,140 N.

Learn more here: brainly.com/question/21413915

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3 years ago
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There are two types of change in matter: physical change and chemical change. ... This is called the Law of Conservation of Matter. It states that matter can never be created or destroyed, only changed and rearranged.

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viktelen [127]
Hey mate
Here is your answer
Option A)
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The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.
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<h2>a is b is c is</h2>

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