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tatiyna
3 years ago
8

How much energy does a pair of 800w hair straighteners transfer every second?

Physics
2 answers:
Solnce55 [7]3 years ago
5 0

Answer: 800 J

Explanation:

Power is the rate between the energy transferred (E) and the time taken (t):

P=\frac{E}{t}

In this problem, the hair straightener has a power of P = 800 W. therefore, the energy transferred in t = 1 second is

E=Pt=(800 W)(1 s)=800 J

babymother [125]3 years ago
3 0
Power is a measure of the rate of energy or work done on a system. It has units of energy per time. In SI, Joules per second and is equal to the units of Watts. So, for an 800 Watts hair straightener, the energy transfer per second would be 800 Joules.
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A miner of mass 90kg travels down a slide calculate the potential energy of the miner when he moves15m vertically downwards
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Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh


8 0
3 years ago
During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the
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Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

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½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

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On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small
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5 0
3 years ago
190 kg of water is to be raised by a water pump to a height of 25 meters from the bottom of a well in 60 seconds. What should be
ladessa [460]

Answer:

776.6 w

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Explanation:

given:

Mass, m = 190kg

height change, h = 25m

time elapsed, t = 60 s

acceleration due to gravity, g = 9.81 m/s²

Potential energy required raising 190 kg of water to a height of 25m

= mgh

= 190 x 9.81 x 25

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Power required in 60 s

= Energy required ÷ time elapsed

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6 0
3 years ago
In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added
amid [387]

Answer:

187 J

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ΔQ = ΔW + ΔU

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ΔW : Work. If it done by the system then positive and if it is done on system then negative.

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ΔQ = 79 J

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ΔU = ?

substituting the value in the equation:

79 = -108 + ΔU

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7 0
3 years ago
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