Answer:
![a=5m/s^2](https://tex.z-dn.net/?f=a%3D5m%2Fs%5E2)
Explanation:
Aceleration is a change on the velocity of the object in a given time.
For this case: the initial velocity is
![v_{1}=150m/s](https://tex.z-dn.net/?f=v_%7B1%7D%3D150m%2Fs)
and the final velocity is :
![v_{2}=0 m/s](https://tex.z-dn.net/?f=v_%7B2%7D%3D0%20m%2Fs)
so, the change in velocity is:
![\Delta v =v_{2}-v_{1}=0m/s - (-150m/s) = 150 m/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3Dv_%7B2%7D-v_%7B1%7D%3D0m%2Fs%20-%20%28-150m%2Fs%29%20%3D%20%20150%20m%2Fs)
and the change in time , according to the problem:
![\Delta t=30s](https://tex.z-dn.net/?f=%5CDelta%20t%3D30s)
So, the aceleration is:
![a=\frac{\Delta v}{\Delta t} = \frac{150m/s}{30s} = 5m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%5CDelta%20v%7D%7B%5CDelta%20t%7D%20%3D%20%5Cfrac%7B150m%2Fs%7D%7B30s%7D%20%3D%205m%2Fs%5E2)
When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
To find the answer, we have to know about the rules followed by drawing ray-diagram.
<h3>What are the rules obeyed by light rays?</h3>
- If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
- The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
- The refracted ray follows the same path if the incident light passes through the center of the curve.
Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
Learn more about refraction by a lens here:
brainly.com/question/13095658
#SPJ1
Distance= speed x time
distance = 2.6 m/s x 120s
distance= 312 meters
help show if a straight "trend line" represents the experimental data
Electrostatic force between two points in space is defined as,
![F_e=\dfrac{Q_1Q_2}{4\pi r\epsilon_r\epsilon_0}](https://tex.z-dn.net/?f=F_e%3D%5Cdfrac%7BQ_1Q_2%7D%7B4%5Cpi%20r%5Cepsilon_r%5Cepsilon_0%7D)
The r is the distance between them.
So if,
![1N=\dfrac{Q_1Q_2}{4\pi 2cm\epsilon_r\epsilon_0}\Rightarrow 2\cdot1N=\dfrac{Q_1Q_2}{4\pi\cdot10^{-2}m\cdot\epsilon_r\epsilon_0}](https://tex.z-dn.net/?f=1N%3D%5Cdfrac%7BQ_1Q_2%7D%7B4%5Cpi%202cm%5Cepsilon_r%5Cepsilon_0%7D%5CRightarrow%202%5Ccdot1N%3D%5Cdfrac%7BQ_1Q_2%7D%7B4%5Cpi%5Ccdot10%5E%7B-2%7Dm%5Ccdot%5Cepsilon_r%5Cepsilon_0%7D)
Than,
![\boxed{\dfrac{1}{4}N}=\dfrac{Q_1Q_2}{4\pi\cdot 8cm\cdot\epsilon_r\epsilon_0}\Rightarrow8\dfrac{1}{4}N\Leftrightarrow 2N=\dfrac{Q_1Q_2}{4\pi\cdot10^{-2}m\cdot\epsilon_r\epsilon_0}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B1%7D%7B4%7DN%7D%3D%5Cdfrac%7BQ_1Q_2%7D%7B4%5Cpi%5Ccdot%208cm%5Ccdot%5Cepsilon_r%5Cepsilon_0%7D%5CRightarrow8%5Cdfrac%7B1%7D%7B4%7DN%5CLeftrightarrow%202N%3D%5Cdfrac%7BQ_1Q_2%7D%7B4%5Cpi%5Ccdot10%5E%7B-2%7Dm%5Ccdot%5Cepsilon_r%5Cepsilon_0%7D)
Hope this helps.
r3t40