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tatiyna
4 years ago
8

How much energy does a pair of 800w hair straighteners transfer every second?

Physics
2 answers:
Solnce55 [7]4 years ago
5 0

Answer: 800 J

Explanation:

Power is the rate between the energy transferred (E) and the time taken (t):

P=\frac{E}{t}

In this problem, the hair straightener has a power of P = 800 W. therefore, the energy transferred in t = 1 second is

E=Pt=(800 W)(1 s)=800 J

babymother [125]4 years ago
3 0
Power is a measure of the rate of energy or work done on a system. It has units of energy per time. In SI, Joules per second and is equal to the units of Watts. So, for an 800 Watts hair straightener, the energy transfer per second would be 800 Joules.
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Which of the substances in the chart has the greatest density?
svlad2 [7]
A.gold is the answer. As it's density is 19.32 grams per cubic centimeter which is lot more than the other substances.
 
4 0
3 years ago
Astronomers estimate that a 2
tia_tia [17]
M)³ / 6 = 4.2e9 m³ 
<span>so its mass is </span>
<span>M = 3300kg/m³ * 4.2e9m³ = 1.4e13 kg </span>
<span>and so its KE at 16 km/s = 16000 m/s is </span>
<span>KE = ½ * 1.4e13kg * (16000m/s)² = 1.8e21 J 

</span># of bombs N = 1.8e21J / 4.0e16J/bomb = 44 234 bombs 
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

6 0
3 years ago
At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
3 years ago
A car moves uphill at 40 km/h and then back downhill at 60 km/h. What is the average speed for the round trip?
jok3333 [9.3K]

Answer:

S_a_v_e_r_a_g_e=48km/h

Explanation:

Ok, the average speed can be calculate with the next equation:

S_a_v_e_r_a_g_e=\frac{Total\hspace{3}distance}{Total\hspace{3}time}   (1)

Basically the car cover the same distance "d" two times, but at different speeds, so:

Total\hspace{3}distance=2*d

and the total time would be the time t1 required to go from A to B plus the time t2 required to go back from B to A:

Total\hspace{3}time=t1+t2

From basic physics we know:

t=\frac{d}{S1}

so:

t1=\frac{d}{S1}

t2=\frac{d}{S2}

Using the previous information in equation (1)

S_a_v_e_r_a_g_e=\frac{2*d}{\frac{d}{S1} +\frac{d}{S2} }=\frac{2*d}{\frac{d*S2+d*S1}{S1+S2} }

Factoring:

S_a_v_e_r_a_g_e=\frac{2*S1*S2}{S1+S2}   (2)

Finally, replacing the data in (2)

S_a_v_e_r_a_g_e=\frac{2*40*60}{60+40} =48km/h

5 0
3 years ago
H<br>Ggghffyjfdudjhfhghggffghjjdxv
amid [387]

Answer:

H

Ggghffyjfdudjhfhghggffghjjdxv

Explanation: The law of copying

6 0
3 years ago
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