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cestrela7 [59]
3 years ago
14

A tank with a volume of 0.150 m3 contains 27.0oC helium gas at a pressure of 100 atm. How many balloons can be blown up if each

filled balloon is a sphere 30.0 cm in diameter at 27.0oC and absolute pressure of 1.20 atm? Assume all the helium is transferred to the balloons.
Physics
1 answer:
jekas [21]3 years ago
8 0

Answer:

884 balloons

Explanation:

Assume ideal gas, since temperature is constant, then the product of pressure and volume is constant.

So if pressures reduces from 100 to 1.2, the new volume would be

V_2 = \frac{P_1V_1}{P_2} = \frac{100*0.15}{1.2} = 12.5 m^2

The spherical volume of each of the balloon of 30cm diameter (15 cm or 0.15 m in radius) is

V_b = \frac{4}{3}\pir^3 = \frac{4}{3}\pi 0.15^3 = 0.014 m^3

The number of balloons that 12.5 m3 can fill in is

V_2/V_b = 12.5 / 0.014 = 884

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How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g
Nata [24]

Answer:

Heat of vaporization will be 22.59 j    

Explanation:

We have given mass m = 10 gram

And heat of vaporization L = 2.259 J/gram

We have to find the heat required to vaporize 10 gram mass

We know that heat of vaporization is given by Q=mL, here m is mass and L is latent heat of vaporization.

So heat of vaporization Q will be = 10×2.259 = 22.59 J

8 0
3 years ago
Read 2 more answers
When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai
geniusboy [140]

Answer:

The total frictional force is 358.0 newtons

Explanation:

Power is the amount of average work (W) an object does on a period of time (Δt):

P=\frac{W}{\Delta t}

Remember average work is average force (F) times displacement (Δs):

P=\frac{F \Delta s}{\Delta t}

but displacement over time is average speed v=\frac{\Delta s}{\Delta t}, then:

P=Fv (1)

That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

F=\frac{P}{v}

Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308\frac{m}{h} = 62.5 \frac{m}{s}, then:

F=\frac{22380}{62.5}=358.0 N

6 0
3 years ago
Read 2 more answers
Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2
sleet_krkn [62]

-- Accelerating at the rate of 8 m/s², Andy's speed
   after 30 seconds is

                                   (8 m/s²) x (30.0 s)  =  240 m/s .

-- His average speed during that time is

                                 (1/2) (0 + 240 m/s)  =  120 m/s .

-- In 30 sec at an average speed of 120 m/s,
   Andy will travel a distance of
                                                 (120 m/s) x (30 sec) = 3,600 m

                                                                                = 3.6 km .

"But how ? ! ?", you ask.

How in the world can Andy leave a stop light and then
cover 3.6 km = 2.24 miles in the next 30 seconds ?

The answer is:  His acceleration of  8 m/s², or about  0.82 G
is what does it for him.

At that rate of acceleration ...

-- Andy achieves "Zero to 60 mph" in 3.35 seconds,
   and then he keeps accelerating.

-- He hits 100 mph in 5.59 seconds after jumping the light ...
   and then he keeps accelerating.

-- He hits 200 mph in 11.2 seconds after jumping the light ...
   and then he keeps accelerating.

-- After accelerating at 8 m/s² for 30 seconds, Andy and his
   car are moving at  537 miles per hour !
   We really don't know whether he keeps accelerating,
    but we kind of doubt it. 

A couple of observations in conclusion:

-- We can't actually calculate his displacement with the information given.
   Displacement is the distance and direction between the starting- and
   ending-points, and we're not told whether Andy maintains a straight line
   during this tense period, or is all over the road, adding great distance
   but not a lot of displacement.

-- It's also likely that sometime during this performance, he is pulled
   over to the side by an alert cop in a traffic-control helicopter, and
   never actually succeeds in accomplishing the given description. 
5 0
3 years ago
I need help with this. -3x-7=18​
miskamm [114]

the answer is

-8.33333333

4 0
3 years ago
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After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38
ddd [48]

Answer:

64.2 m/s

Explanation:

We are given that

Speed ,v=38 m/s

We have to find the maximum speed when his car reach on flat ground.

Using dimensional analysis

F_{res}\propto v^2

If 35% acceleration reduced by F(res) at 38 m/s

Then, 100% acceleration  can be reduced  by F(res) at v' m/s

\frac{F_1}{F_2}=\frac{v^2}{v'^2}

v'^2=\frac{F_2}{F_1}v^2

v'=v\sqrt{\frac{F_2}{F_1}}

Substitute the values

v'=38\times \sqrt{\frac{100}{35}}

v'=64.2 m/s

Hence, the maximum speed when his car can reach on flat ground=64.2 m/s

3 0
2 years ago
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