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astraxan [27]
2 years ago
5

To show the bonding in a molecule or polyatomic ion, we can use a lewis structure, which shows bonding electron pairs as ______

and any nonbonding electrons as ______.
Chemistry
1 answer:
ArbitrLikvidat [17]2 years ago
3 0

Lewis structure, which shows bonding electron pairs as Lines and any nonbonding electrons as dots.

A chemical bond is  holds atoms collectively in molecules. Bonds get up from the electrostatic forces between definitely charged atomic nuclei and negatively charged electrons.

Lewis symbols to describe valence electron configurations of atoms and monatomic ions. A Lewis image consists of an elemental image surrounded by way of one dot for each of its valence electrons: parent 1 suggests the Lewis symbols for the factors of the 0.33 length of the periodic table.

Lone pairs are discovered in the outermost electron shell of atoms. They may be diagnosed with the aid of using a Lewis shape. Electron pairs are therefore taken into consideration lone pairs if two electrons are paired however aren't utilized in chemical bonding.

It is  representation of the valence shell electrons in a molecule. it's far used to expose how the electrons are arranged round individual atoms in a molecule. Electrons are shown as dots or for bonding electrons as a line between the two atoms.

Learn more about bonding in a molecule here:-brainly.com/question/2615067

#SPJ4

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Determine the potential deaths resulting from the following exposure to chlorine:
jekas [21]

Answer:

For each scenario as following:

A. 3 Potential deaths by chlorine exposure

B. 1 Potential deaths by chlorine exposure

C. 3 Potential deaths by chlorine exposure

Explanation:

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6 0
3 years ago
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

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