If the resistance in a circuit connected to a constant current is halved, how is the voltage in the circuit affected?.
1 answer:
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Answer:
Refractive index of unknown liquid = 1.56
Explanation:
Using Snell's law as:
Where,
is the angle of incidence ( 65.0° )
is the angle of refraction ( 53.0° )
is the refractive index of the refraction medium (unknown liquid, n=?)
is the refractive index of the incidence medium (oil, n=1.38)
Hence,
Solving for ,
Refractive index of unknown liquid = 1.56
According to Ohm's Law:
Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.
Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.