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3 years ago

Name an element in the third period (row) of the periodic table with a total of 4 3p electrons

Chemistry

1 answer:

Wittaler [7]3 years ago

3 0

Answer:

sulfur

Explanation:

sulfur has 4p electrons.

phosphorus has 3p electrons.

The question is asking which one has 4

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A buffer solution is prepared by adding NaH2PO4 to a solution of H3PO4 (phosphoric acid).

Softa [21]

Answer:

remains the same

Explanation:

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3 years ago

If oil spills continue, all of the following should be expected except (2 points)

Ilia_Sergeevich [38]

Answer:

Polluted ground water.

Explanation:

The rocks through which water flows into the ground sieves most of the contaminants whose molecules are larger than most bacteria. Such molecules include but are not limited oil molecules. Therefore as it descends to the lower levels of the soil profile, water is subjected to continuous filtration by the layers and it is the least susceptible to contamination by oil spills.

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3 years ago

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What two dose the transfer of light energy require

IrinaK [193]

Answer:

Magnetic fields and Electric fields

Explanation:

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3 years ago

What volume of beaker contains exactly 2.23x10^-2 mol of nitrogen gas at STP?

nikklg [1K]

Answer:

V = 0.5 L

Explanation:

Given data:

Moles of nitrogen = 2.23×10⁻² mol (0.0223 mol)

Temperature = 273 K

Pressure = 1 atm

Volume = ?

Solution:

PV = nRT

V = nRT / P

V = 0.0223 mol × 0.0821 atm. mol⁻¹. L . k⁻¹ × 273 K / 1 atm

V = 0.5 L

4 0

4 years ago

Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What

Leto [7]

Answer: The nuclide symbol of X is $^{231}_{90}\textrm{Th}$

Explanation:

The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.

The general equation representing alpha decay process is:

$_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}$

For the given equation :

$^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}$

As the atomic number and mass number must be equal on both sides of the nuclear equation:

$^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}$

Thus the nuclide symbol of X is $^{231}_{90}\textrm{Th}$

5 0

3 years ago