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mr_godi [17]
3 years ago
15

How do you balance a chemical equation

Chemistry
1 answer:
Dominik [7]3 years ago
6 0
There should be mass balance and the charge balance between the reactants and the products

Mass balance : total no of individual atoms of each type should be balanced before and after the reaction

Charge balance : Overall charge of the reactants should be balanced with the overall charge of the products

You can balance,

1)by just looking at it

2)by Algebraic method given above or

3)by the redox method

You need to know how to get the oxidation numbers in order to use the oxidation method

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Because it is made up of sodium, a metal, and carbon, a nonmetal.

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Why did you get that wrong?
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5 0
3 years ago
When the equation Al2(SO4)3 + NaOH + Al(OH)3 + Na2SO4 is correctly balanced, what is the coefficient of Al(OH)3?
nevsk [136]
The balanced chemical formula should be Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4

Therefore the coefficient of Al(OH)3 is 2!

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4 0
3 years ago
If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of
navik [9.2K]

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

Learn more about molarity: brainly.com/question/10053901

6 0
2 years ago
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